Use /etc/security/limits.conf file to limit amount of concurrent logins for a specific user.
Use the /etc/security/limits.conf record to restrict aid use for all packages. That is from the pam_limits module of the Plugable Authentication Modules (PAM) module set. Entries in /etc/security/limits.conf comprise the subsequent: Entity type limit value.
A pluggable authentication module (PAM) is a mechanism to combine multiple low-level authentication schemes right into an excessive-stage Application programming interface (API). PAM allows applications that depend on authentication to be written independently of the underlying authentication scheme.
A module is a software program component or a part of an application that includes one or greater routines. One or more independently developed modules make up an application. A company-level software application may contain numerous one-of-a-kind modules, and each module serves unique and separate business operations.
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Answer: The use of promotional signage
Explanation:
A promotional signage is a method of advertisement where special offers are displayed at strategic points by a business to the public to attract customers to patronize the business. Manila in her is making use of promotional signage to draw the attention of potential buyers to her store.
Answer:
Two categories of expenses in merchandising companies are c. cost of goods sold and operating expenses
Explanation:
Merchandising Companies will incur direct expenses related to their trading activities in relation to each of their sales and these are known as cost of goods sold. Cost of Goods Sold is an expense in the Trading Account.
However, the Merchandising Company will also incur other indirect expenses to maintain its trading and are not directly related to each sale of their merchandise. For example the cost of Administration Work and Depreciation of its equipment. These are known as Operating Expenses. Operating Expenses are expenses in the Profit and loss Account
Answer:
C = 0.05*x + 34
Explanation:
There are several ways to approach this problem. However, we will follow a logical and simple procedure.
It is always possible to write any linear equation as:
y = mx + b, where:
m = slope
b = y-intercept (value when x = 0)
The problem statement guarantees us that b=34, because if we do not drive any mile (x=0), then the cost should be equal to $ 34. Also, we know that m=0.05, because every driven mile (increase in x by 1) the cost should increase by $5. Therefore, we can write the linear equation as:
y = 0.05x + 34
Changing the dependent variable y for C (to relate it with the cost) we have that:
C = 0.05x + 34
