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Rudik [331]
3 years ago
7

suppose you know that two angles,angle A and B,are supplementary.The measure of angle A is 5 times the measure of angle B. Find

the measures of angles.??
Mathematics
2 answers:
kirill115 [55]3 years ago
4 0
First of all let's review some vocabulary:
Supplementary : a fancy word that means "the angles add up to 180" .
If we know that the total is 180 , then the values of A and B are .......
Let's set up an equation :
5x + x = 180
5x symbolizes "The measure of angle A is 5 times "
X symbolizes "the measure of angle B"
And 180 "the total"
Now we solve the equation
5x+x=180
6x=180
6x/6 =180/6
X=30
We just found the measure of angle B , now let's find A.
So the measure if angle A is 5 times the measure of angle B . We already know the measure of angle B , so we just multiply 30 by 5.
30 times 5=150
Angle A=150
Angle B=30
Let's check the answers
150 + 30 = 180
They add up to 180 , which means they are correct .
Morgarella [4.7K]3 years ago
3 0
Angle A is 150
Angle B is 30 
Supplementary= 180, so....
Angle A + Angle B = 180
150 + 30= 180

hope this helps
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padilas [110]

Hello :)

3x+y=27

-3x+4y= -42

+____________

(3x -3x) + (y+4y) = (27-42)

0 + 5y = -15

y = -3

Put "-3" for "y" in the system:

3x + y =27

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x = 10

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Have a nice day :)

8 0
3 years ago
What is the answer ?
maks197457 [2]

Answer:

a rational number

Step-by-step explanation:

a rational number + a rational number will always be a rational number.

7 0
3 years ago
In terms of rigid transformations (reflections, rotations, and translations), what does this difference represent?
makvit [3.9K]

Solution:

There are four kinds of rigid transformations.

1. Reflection

2. Rotation

3. Translation

4. Dilation

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4 0
4 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
1
olga nikolaevna [1]

Answer:

Fraction of the original board left = \frac{2}{15}

Step-by-step explanation:

Let the length of the board is = l feet

Marty saws off \frac{1}{5} of a wooden board.

Length of the board left = l - (\frac{1}{5})l

                                        = (\frac{4}{5})l feet

He saws off \frac{3}{4}th of the remaining board,

Board left = (\frac{4}{5})l-[(\frac{4}{5})l\times (\frac{3}{4})]

                = \frac{4}{5}l-\frac{3}{5}l

                = \frac{1}{5}l feet

He finally saws off \frac{1}{3}rd of the remaining board.

Board left = \frac{1}{5}l-[\frac{1}{5}\times \frac{1}{3}]l

                = (\frac{1}{5}-\frac{1}{15})l

                = \frac{2}{15}l feet

Fraction of the original board left = \frac{\frac{2}{15}l}{l}

                                                       = \frac{2}{15}

6 0
3 years ago
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