Answer:
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Step-by-step explanation:
Answer:
108 books.
Step-by-step explanation:
Let the number of magazines = m
Let the number of books = b
<u>Given the following data;</u>
Total number of m & b = 162
<em>Translating the word problem into an algebraic equation, we have;</em>
......equation 1
......equation 2
<em>Substituting equation "1" into equation "2" we have;</em>
m = 54
Now to find the number of books;
Substituting the value of "m" into the equation, we have;
<em>b = 108</em>
<em>Therefore, the total number of books in the library is 108 books. </em>
Answer:
Mean = 58.25
Median = 57.5
Mode = 49
Step-by-step explanation:
We are given the following data set:
55, 51, 74, 61, 67, 60, 49, 49
Formula:
Sorted data:
49, 49, 51, 55, 60, 61, 67, 74
Mode is the entry with highest frequency.
49 appeared two times.
Mode = 49
Formula:
All these are less than 60 seconds, which indicates that students perceive 1 minute to pass sooner than it actually has.
Answer:
(2,7)
Step-by-step explanation:
y=6x-5
y=x+5
Since they are both equal to y, set them equal to each other
6x-5 = x+5
Subtract x from each side
6x-x-5 = x+5-x
5x-5 = 5
Add 5 to each side
5x-5 +5 = 5+5
5x=10
Divide by 5
5x/5 = 10/5
x=2
y = x+5
y = 2+5
y =7
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E
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Work Shown
Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A
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Problem 47)
If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago
So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B
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Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
