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Assoli18 [71]
3 years ago
8

Identify the linear equation.

Mathematics
1 answer:
Olin [163]3 years ago
6 0

Answer:

D

Step-by-step explanation:

Linear equation should not have any power, or fractions

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Find x, y and z<br> 82"<br> 54
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What is the quotient to four dived by fifty
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Find the distance between 2-3i and 9+21i<br> =[?]
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Find the domain of the function f of x equals square root of the quantity twelve x plus twenty four
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The domain is related to the x-value of the function. In this case, the goal of finding the domain is to make sure that the number under the radical sign is positive. The number that makes the function under the radical sign is -2. Hence this is the minimum number and the domain is from -2 to positive infinity. 
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3 years ago
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair a
vesna_86 [32]
Chair=x

Table=y

Desk=z

\begin{Bmatrix}x+y&=&40\\y+z&=&83\\x+z&=&77\end{matrix}

keep the first row as normal, then in the other ones, we can isolate Y and X

\begin{Bmatrix}x+y&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

now we can replace at first row...

\begin{Bmatrix}(77-z)+(83-z)&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}160-2z&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&40-160\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&-120\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}z&=&60\\y&=&83-z\\x&=&77-z\end{matrix}

now we can replace the Z to discovery the other value

\begin{Bmatrix}z&=&60\\y&=&83-60\\x&=&77-60\end{matrix}

\boxed{\boxed{\boxed{\begin{Bmatrix}Chair&=&17\\Table&=&23\\Desk&=&60\end{matrix}}}}
6 0
3 years ago
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