Question

A worker carries jugs of liquid soap from a production line to a packing area, carrying 4 jugs per trip. If the jugs are packed into cartons that hold 7 jugs each, how many jugs are needed to fill the last partially filled carton after the worker has made 17 trips?
A. 1
B. 2
C. 4
D. 5
E. 6

Answer 1

Answer:

B. 2

Step-by-step explanation:

We have been given that a worker carries jugs of liquid soap from a production line to a packing area, carrying 4 jugs per trip.

Since worker has made 17 trips, so total number of hugs of liquid soap would be 17 times number of jugs carried per trip.

$17\times 4=68$.

Since each carton holds 7 jugs, so number of cartoons would be $\frac{68}{7}$.

$\frac{68}{7}\Rightarrow \frac{63+5}{7}=9\frac{5}{7}$

We can see that there are 9 completely filled cartoons and there are 5 jugs remaining, so we need $7-5=2$ jugs.

Therefore, we need 2 jugs to fill the 10th cartoon and option B is the correct choice.