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tresset_1 [31]
3 years ago
14

Which equation DOES NOT represent the problem?

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
6 0

the last option

42t=28t+0.25


hope this helps

<3

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The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
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together they represent a point, which is the center
So (h,k) is (x,y)

The asymptote is y-k = +/- b/a (x-h)
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I have these factoring questions I need help with.
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f(x)=4x^2+4x-3

1. Determine y-intercept.

<em>The y-intercept is (0,-3). Substitute x = 0 in the equation as we get f(x) = -3 as the y-intercept.</em>

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<em>Factor the polynomials first. </em>(2x-1)(2x+3) <em>This is the factored form. The zeros are the roots of equation. Therefore, the zeros are 1/2 and -3/2</em>

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<em />f'(x)=2(4x^{2-1})+1(4x^{1-1})-0\\f'(x)=8x+4<em />

<em>Then let f'(x) = 0 to find the Axis of Symmetry.</em>

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4. Determine the vertex.

<em>Substitute the value of Axis of Symmetry in f(x).</em>

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<em>The vertex represents the minimum point. The graph is upward, meaning the minimum point is the point that gives the LOWEST Y-VALUE. </em>

7. Graph f(x)

<em>Unfortunately I won't be able to graph. But I can tell you to graph a parabola that has the most curve at the vertex and intercepts y-axis at (0,-3).</em>

<em>--------------------------- </em>End of Part 1 --------------------------------

2. Write the general form of Quadratic Function in standard form.

y=ax^2+bx+c

<em>The graph can be easily determined about the y-intercept and being an upward or downward parabola along with how narrow or wide the parabola is. </em>

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y=(x+a)(x+b)\\y=(x-a)(x-b)\\y=(x+a)(x-b)\\y=(x-a)(x+b)

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y=a(x-h)^2+k

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Answer:

see below

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Order of operations is parenthesis, exponents, multiplication, division, addition, subtraction.

since there are no exponents in this problem the next step is -2(2.2)

Simplify the previous step and you get -4.4

final answer is -7.6 - 4.4 = -12

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