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3 years ago

Someone please help me

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

8 0

knowing angle b is 45 to find length of c

then both leg are the same length

so c = square root of 11^2 + 11^2 = 15.56

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Are 9 and 1/9 reciprocals?

Harlamova29_29 [7]

Answer:

yes

Step-by-step explanation:

9 can be represented as 9/1, which is the reciprocal of 1/9.

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3 years ago

Read 2 more answers

Please help me solve this question<br>4x+6<-6

stiks02 [169]

4x + 6 < -6
subtract 6 from both sides
4x < -12
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4 years ago

Tarantulas are one of the largest spiders on Earth. A

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Tarantulas are 5.9 centimeters longer.

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2 years ago

From the diagram below, given the side lengths marked, and if we know that < C is congruent to < E, we can say that ___.

Lana71 [14]

Since we know that <C is congruent to <E, we can say that: A. the two triangles are similar by SAS.

<h3>The properties of similar triangles.</h3>

In Geometry, two triangles are similar when the ratio of their corresponding sides are equal in magnitude and their corresponding angles are congruent.

Ratio = BC/AC = 6/3 = 2.

Ratio = FE/DE = 4/2 = 2.

Thus, the ratio of their corresponding sides are equal in magnitude i.e BC/AC ≡ FE/DE.

Since we know that <C is congruent to <E, we can say that the two triangles are similar by side, angle, side (SAS) criterion.

Read more on congruency here: brainly.com/question/11844452

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2 years ago

A piece of cardboard is 1 meter by 1/21/2 meter. A square is to be cut from each corner and the sides folded up to make an open-

12345 [234]

Answer:

The maximum dimensions of the box:

Length of the box = 0.788676 m

Breadth of the box = 0.288676 m

Step-by-step explanation:

Original piece of cardboard is a square with sides of length s.

Length of the card board = l = 1 m

Breadth of cardboard = b = 1/2 m = 0.5 m

Squares with sides of length x are cut out of each corner of a rectangular cardboard to form a box.

Now, length of the box = L = 1 - 2x

And breadth of the box = B = 0.5 - 2x

Height of the box ,H = x

Volume of the box ,V= L × B × H

$\frac{dV}{dx}=\frac{(1 -2x)(0.5-2x)x}{dx}$

$\frac{dV}{dx}=\frac{d(0.5x-3x^2+4x^3)}{dx}$

$\frac{dV}{dx}=0.5-6x+12x^2$

$\frac{dV}{dx}=O$

x = 0.394338 , 0.105662

$\frac{d^2V}{(dx)^2}=-6+24x$

When , $x=0.105662$ , $\frac{d^2V}{(dx)^2}$ (maxima)

The maximum dimensions of the box:

Length of the box = L = 1 - 2x = 1 - 2(0.105662) m = 0.788676 m

Breadth of the box = B = 0.5 - 2x = 0.5 - 2(0.105662) m = 0.288676 m

6 0

3 years ago