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3 years ago

What is the image point of ( -5,0 ) after a translated left 2 units and down 3 units ?

1 answer:

5 0

Answer: ( -7 , -3 )

Step by step:
The point: ( X , Y )
Left 2 units = change X by -2
So, -5 subtract by 2 equals -7
Down 3 units = change Y by -3
So, 0 subtract by 3 equals -3
Now, X = -7 and Y = -3, so the answer is ( -7 , -3 )

Hope this helps! Please tell me if I did anything wrong, thank you!

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NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

Which is the solution to the inequality? y + 15 < 3

Yuki888 [10]

Answer:

y < - 12

Step-by-step explanation:

y + 15 < 3 ( subtract 15 from both sides )

y < - 12

4 0

2 years ago

Read 2 more answers

Factor completely x2 + 20x + 99

Bad White [126]

$x^2 + 20x + 99=x^2+9x+11x+99=x(x+9)+11(x+9)=(x+11)(x+9)$

6 0

2 years ago

For what value of x is line a parallel to line b? (Yo, please help me so I can go to sleep.)

iogann1982 [59]

X=20

If they're parallel the other number in the same spot as 5x+15 equals that, so 5x+15=115 because if they are parallel they're the same if same spot and same line going through them.

115-15 = 100
5x=100
Divide by 5 both sides
X=20

If x=20 then these lines would be parallel

6 0

3 years ago

What is the prime factorization of 36

artcher [175]

Answer:

$2^{2} x 3^{2}$

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the image point of ( -5,0 ) after a translated left 2 units and down 3 units ?​

What is the image point of ( -5,0 ) after a translated left 2 units and down 3 units ?