Recall that r^2 = x^2 + y^2, so that r = sqrt(x^2+y^2).
y
r = 3 sin g becomes sqrt(x^2+y^2) = 3*-----------------------
sqrt(x^2+y^2)
Squaring both sides,
9y^2
x^2+y^2 = -----------------
x^2 + y^2
If this is correct (and I'm not convinced that it is), then (x^2+y^2)^2 = 9y^2
shows the relationship between x and y. Can anyone improve on this result?
Answer by JKismyhusbandbae:
Answer:
The coordinates of A would be (-1, 2)
Step-by-step explanation:
In order to find this, use the mid-point formula.
(xA + xB)/2 = xM
In this, the xA is the x value of point A, xB is the x value of point B, and xM is the x value of M. Now we plug in the known information and solve for xA.
(xA + 5)/2 = 2
xA + 5 = 4
xA = -1
Now we can do the same using the midpoint formula and the y values.
(yA + yB)/2 = yM
(yA + 10)/2 = 6
yA + 10 = 12
yA = 2
This gives us the midpoint of (-1, 2)
