Answer:
Step-by-step explanation:
Given function is,
In the given exponential function,
Base of the function = 
By the property of an exponential function,
1). If the base is between 0 and 1, function will be a growth function.
2). If the base is greater than 1, function will be a decay function.
Therefore, given function is a decay function.
Input-output table,
x -2 -1 0 1 2
y 
By plotting these points we can get the graph of the function.
Domain: (-∞, ∞)
Range: (0, ∞)
y-intercept: 1
Asymptote: y = 0
Answer:
The required rectangular form of the given complex polar form :
z1 = -3√2 - 3√2i
Step-by-step explanation:
![z_1=6[\cos (\frac{5\pi}{4}) + i\sin(\frac{5\pi}{4})]...........(1)\\\\Now,\cos (\frac{5\pi}{4})=\cos(\pi+\frac{\pi}{4})\\\\=-\cos(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}\\\\And,\sin (\frac{5\pi}{4})=\sin(\pi+\frac{\pi}{4})\\\\=-\sin(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}](https://tex.z-dn.net/?f=z_1%3D6%5B%5Ccos%20%28%5Cfrac%7B5%5Cpi%7D%7B4%7D%29%20%2B%20i%5Csin%28%5Cfrac%7B5%5Cpi%7D%7B4%7D%29%5D...........%281%29%5C%5C%5C%5CNow%2C%5Ccos%20%28%5Cfrac%7B5%5Cpi%7D%7B4%7D%29%3D%5Ccos%28%5Cpi%2B%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5C%5C%5C%5C%3D-%5Ccos%28%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5C%5C%5C%5C%3D-%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%5C%5C%5C%5CAnd%2C%5Csin%20%28%5Cfrac%7B5%5Cpi%7D%7B4%7D%29%3D%5Csin%28%5Cpi%2B%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5C%5C%5C%5C%3D-%5Csin%28%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5C%5C%5C%5C%3D-%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D)
On substituting the obtained values in equation (1)
![z_1=6[\frac{-1}{\sqrt{2}}-i\cdot \frac{1}{\sqrt{2}}]\\\\\implies z_1=-3\sqrt{2}- 3\sqrt{2}\cdot i](https://tex.z-dn.net/?f=z_1%3D6%5B%5Cfrac%7B-1%7D%7B%5Csqrt%7B2%7D%7D-i%5Ccdot%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%5D%5C%5C%5C%5C%5Cimplies%20z_1%3D-3%5Csqrt%7B2%7D-%203%5Csqrt%7B2%7D%5Ccdot%20i)
Hence, the required rectangular form of the given complex polar form :
z1 = -3√2 - 3√2i
Answer:
The answer would be B
Step-by-step explanation:
Your mean is 602.4, and your median is 609
Ok so assuming that the 'x' means multiply and not 'x' as in placeolder we do
PEMDAS
parenthaseees
exponents
multipilcation or division
additon or subtraction
parethasees simplify first
(8+7)=15
(9-3)=6
now we have
2x(15)-6/2x(6)
multiply
2x15=30
6/2x6=36/2=18
now we have
30-18
12
answer is 12
58a + 49 is the correct answer
