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tamaranim1 [39]
3 years ago
6

How many moles of oxygen gas would be needed to completely burn 8 moles of hydrogen sulfide?

Chemistry
2 answers:
aliya0001 [1]3 years ago
5 0

Answer: 12 mol of O2

Reason being is because of this equation. Hope you understand this.

Equation: <u>2 H2s</u> (g) +<u> 3 o2</u> (g) + <u>2 SO2</u> (g) + <u>2 H2O</u> (g)

Before: <u>8 mol</u>   <u>xs mol</u>    <u>0 mol</u><u> </u>     <u>0 mol</u>

Change: <u>-8 mol</u>   <u>-12 mol</u>   <u>+8 mol</u>   <u>+8 mol</u>

After: <u>0 mol</u>   <u>XS mol</u><u> </u>   <u>+8 mol</u>   <u>+8 mol</u>

<u>So therefore, your answer is 12 mol. Hope this helps and please mark brainliest if this truly and deeply helped you. Stay safe and have a nice day or night!</u>

OleMash [197]3 years ago
4 0
You would need 12 moles of O2
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Answer:

<h3>The answer is 3.44 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 17.2 g

volume = 5 cm³

We have

density =  \frac{17.2}{5}  \\

We have the final answer as

<h3>3.44 g/cm³</h3>

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Which of the following represents the relative charge of proton
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A sample of argon has a volume of 1.2 L at STP. If the temperature is increased to 21 c and the pressure is lowered to 0.80 atm,
Nuetrik [128]

Answer:

The new volume is 1.62 L

Explanation:

Boyle's law says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." It is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. So this law indicates that the quotient between pressure and temperature is constant.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T}=k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law.

\frac{P*V}{T}=k

Having an initial state 1 and a final state 2 it is possible to say that:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Standard temperature and pressure (STP) indicate pressure conditions P = 1 atm and temperature T = 0 ° C = 273 ° K. Then:

  • P1= 1 atm
  • V1= 1.2 L
  • T1= 273 °K
  • P2= 0.80 atm
  • V2= ?
  • T2= 21°C= 294 °K

Replacing:

\frac{1 atm* 1.2 L}{273K} =\frac{0.8 atm*V2}{294K}

Solving:

V2=\frac{1 atm*1.2 L}{273 K} *\frac{294 K}{0.8 atm}

V2= 1.62 L

<u><em>The new volume is 1.62 L</em></u>

<u><em></em></u>

8 0
3 years ago
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