3. (a) The nitrogen oxide (NO) molecule has a bond length of 140 pm. Calculate the dipole moment, in Debyes, that results if the
charges on N and O were 2 and 2-, respectively. (Include the formula for the calculation in your solution)(b) If the experimentally measured dipole moment is 1.85 D, what is the magnitude (in units of e') of the charges on N and O. (Include the equation in your solution)
1 answer:
Answer:
The calculations is shown in the attached file.
Explanation:
- The concept of dipole moment is applied here. the size of the dipole moment is given by multiplying the size of the charge by the distance apart.
- For simpler molecules, the sizes of the dipole moments are approximately proportional to the difference between the electronegativities of the atoms. Dipole moments are usually measured in debyes (D).
Dipole moments (μ) = q x r
The detailed calculation is shown in the attachment.
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Answer:
ΔS=0.148 KJ/K
Explanation:
Given that
Q = 100 KJ
T₁=200°C
T₁=200+273 = 437 K
T₂=5°C
T₂=5 + 273 = 278 K
Reservoir 1 is rejecting heat that is why it taken as negative while the reservoir 2 is gaining the heat that is why it is taken as positive.
So the total change in entropy given as
ΔS= - Q/T₁ + Q/T₂
ΔS= - 100/473 + 100/278 KJ/K
ΔS=0.148 KJ/K
