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Snowcat [4.5K]
3 years ago
15

An opinion poll surveyed 900 people and reported that 36% believe a certain governor broke campaign financing laws in his electi

on campaign.a. Calculate a 95% confidence interval for the population proportion of people who believe the governor broke campaign financing laws. (Round your answers to three decimal places.)
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

The confidence Interval = (0.329, 0.391)

Step-by-step explanation:

Formula for the Confidence Interval for proportion =

p ± z × √p(1 - p)/n

where

p = x/n

From the question

n = 900 people

x = 36% of 900 people

= 36/100 × 900

= 324

z = z score of 95% confidence Interval

z = 1.98

p = x/n

= 324/900

= 0.36

Confidence Interval = p ± z × √p(1 - p)/n

= 0.36 ± 1.96 × √0.36 (1 - 0.36)/900

= 0.36 ± 1.96 ×√0.36 (0.64)/900

= 0.36 ± 1.96 × √0.000256

= 0.36 ± 1.96 × 0.016

= 0.36 ± 0.03136

Confidence Interval = 0.36 ± 0.03136

= 0.36 - 0.03136

= 0.32864

Approximately to 3 decimal places = 0.329

= 0.36 + 0.03136

= 0.39136

Approximately to 3 decimal places = 0.391

Therefore, the 95% confidence interval for the population proportion of people who believe the governor broke campaign financing laws = (0.329, 0.391)

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Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
Area of rectangle with diagonal of 5 in but length not given
sergij07 [2.7K]

Draw a rectangle with diagonal 5 in. Inside this rect. are 2 acute triangles of hypotenuse 5. Note that 3^2 + 4^2 = 5^2; thus the width of the rect. is 3 and the length is 4, with the result that the hypo. is sqrt(3^2+4^2), as expected.




3 0
3 years ago
on the football team, two out of every seven players are seniors. if the team has 84 players, how many are not seniors.
zaharov [31]

There are 60 players on football team that are not seniors.

Step-by-step explanation:

<u>Method 1:</u>

Given

Total students = 84

Also given that

2 out of 7 are seniors

Which is 2/7

So in order to find the total number of seniors we will multiply the whole number of students to 2/7

Senior\ students = \frac{2}{7} * 84\\= 24

So there are 24 seniors on the football team.

Players that are not seniors = 84 - 24 = 60

There are 60 players who are not seniors.

<u>Method 2:</u>

We can divide the total number by 7, to get how many sets of 7 players will be there

= 84/7 = 12

Now,

Multiplying 12 with 2 will give us the number of seniors in football team.

12*2 = 24 seniors

So,

Not seniors =84-24 = 60

Keywords: Percentage, Units

Learn more about percentage at:

  • brainly.com/question/4710621
  • brainly.com/question/4767370

#LearnwithBrainly

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3 years ago
What is the square root of 9
Nuetrik [128]
It is 3. Because a square root is anything times itself to make an answer. For example:
3 \times 3 = 9 \\ so \\  \sqrt{9 }  = 3
8 0
3 years ago
Read 2 more answers
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
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