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Rasek [7]
3 years ago
6

What is the area of a parallelogram whose vertices are A(−1, 12) , B(13, 12) , C(2, −5) , and D(−12, −5) ?

Mathematics
2 answers:
nlexa [21]3 years ago
8 0
So idk how i'm going to show this w/out graph paper, so bear with me on the answer.
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Just count the spaces between the points. Since it's a parallelogram, that means that length of CD= length of AB, and length of DB= length of BC, so using either length(s) is fine.
By counting we know that the length for CD is 14.
Then count the distance between D and A (or C and B). this is including the x-distance, not just the y, so we end up with 27. Then 27×14=378units²
Idk if I did this right, but I tried my best  :D
Fittoniya [83]3 years ago
5 0

Answer:

The answer is actually 238 units squared.

Step-by-step explanation:

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This is Pancho... 1 thanks equals one friend for him

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A dozen eggs cost 3.84 at this rate how much would 50 eggs cost
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Answer:

50 eggs would cost 16$

Step-by-step explanation:

A dozen eggs is 12. So for 4 dozen eggs, you get 48. 48 eggs is 15.36$. If you divide the 3.84 to 12, you will get the individual price for each egg. The individual price for each egg is .32 cents. You need to add 2 more eggs to the 4 dozen to get 50 eggs. You times .32 to 2 and you get .64. After that you add .64 to the price of the 4 dozen eggs and you will get 16$

Simple version:

dozen eggs =12, cost 3.84$

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2 years ago
A banks loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviati
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Answer:

2.87%

Step-by-step explanation:

We have the following information:

mean (m) = 200

standard deviation (sd) = 50

sample size = n = 40

the probability that their mean is above 21.5 is determined as follows:

P (x> 21.5) = P [(x - m) / (sd / n ^ (1/2))> (21.5 - 200) / (50/40 ^ (1/2))]

P (x> 21.5) = P (z> -22.57)

this value is very strange, therefore I suggest that it is not 21.5 but 215, therefore it would be:

P (x> 215) = P [(x - m) / (sd / n ^ (1/2))> (215 - 200) / (50/40 ^ (1/2))]

P (x> 215) = P (z> 1.897)

P (x> 215) = 1 - P (z <1.897)

We look for this value in the attached table of z and we have to:

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in picture

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2 years ago
Abby used the law of cosines for TriangleKMN to solve for k.
torisob [31]

Answer:

  m∠K = 37° and n = 31

Step-by-step explanation:

A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:

  • a² = b² +c² -2bc·cos(A)
  • k² = 31² +53² -2·31·53·cos(37°)

<h3>Comparison</h3>

Comparing the two equations, we note these correspondences:

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  • b = 31
  • c = 53
  • A = 37°

Comparing these values to the given information, we see that ...

  • KN = c = 53 . . . . . . . . . . matching values 53
  • NM = a = k . . . . . . . . . . . matching values k
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  • ∠K = ∠A = 37° . . . . . . . matching side/angle names

Abby apparently knew that ∠K = 37° and n = 31.

__

<em>Additional comment</em>

Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.

Vertex and angle K are opposite side k, also called side NM in this triangle.

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1 year ago
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