What is the area of a parallelogram whose vertices are A(−1, 12) , B(13, 12) , C(2, −5) , and D(−12, −5) ?
2 answers:
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Graph using slope and the y intercept
So y=x+5
You would plot the y intercept (0,5) and then go up 1 and to the right 1
The next graph plot y intercept (0,-1) and then go down 2 and to the right 1
And should look like the image
And your solution should be (-2,3) which is option c
So y=x+5
You would plot the y intercept (0,5) and then go up 1 and to the right 1
The next graph plot y intercept (0,-1) and then go down 2 and to the right 1
And should look like the image
And your solution should be (-2,3) which is option c
Answer:
Option d) is correct
ie, quotient property
Step-by-step explanation:
Given expression is log 618-log 66=log 63
Now we take log 618-log 66
log 618-log 66 = log [By using quotient property, log
]
= log 63
Therefore log 618- log 66= log 63
Option d) is correct
In the given expression we are using the quotient property