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3 years ago

What is the area of a parallelogram whose vertices are A(−1, 12) , B(13, 12) , C(2, −5) , and D(−12, −5) ?

2 answers:

8 0

So idk how i'm going to show this w/out graph paper, so bear with me on the answer.
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Just count the spaces between the points. Since it's a parallelogram, that means that length of CD= length of AB, and length of DB= length of BC, so using either length(s) is fine.
By counting we know that the length for CD is 14.
Then count the distance between D and A (or C and B). this is including the x-distance, not just the y, so we end up with 27. Then 27×14=378units²
Idk if I did this right, but I tried my best :D

Fittoniya [83]3 years ago

5 0

Answer:

The answer is actually 238 units squared.

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Step-by-step explanation:

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