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4 years ago

How many electrons would hydrogen required to fill up that first shell?

1 answer:

4 0

The first shell can hold up to two electrons maximum.

From the periodic table, we can find that hydrogen has only one electron occupying the first shell. Therefore, hydrogen would require an additional one electron to fill up the first shell.

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Calculate the pH during the titration of 20.00 mL of 0.1000 M HNO2(aq) with 0.1000 M KOH(aq) after 13.27 mL of the base have bee

Slav-nsk [51]

Answer:

pH = 2.462.

Explanation:

Hello there!

In this case, according to the reaction between nitrous acid and potassium hydroxide:

$HNO_2+KOH\rightarrow KNO_2+H_2O$

It is possible to compute the moles of each reactant given their concentrations and volumes:

$n_{HNO_2}=0.02000L*0.1000mol/L=2.000x10^{-3}mol\\\\n_{KOH}=0.1000mol/L*0.01327L=1.327x10^{-3}mol$

Thus, the resulting moles of nitrous acid after the reaction are:

$n_{HNO_2}=2.000x10^{-3}mol-1.327x10^{-3}mol=6.73x10^{-4}mol$

So the resulting concentration considering the final volume (20.00mL+13.27mL) is:

$[HNO_2]=\frac{6.73x10^{-4}mol}{0.01327L+0.02000L} =0.02023M$

In such a way, we can write the ionization of this weak acid to obtain:

$HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+$

So we can set up its equilibrium expression to obtain x as the concentration of H3O+:

$Ka=\frac{[NO_2^-][H_3O^+]}{[HNO_2]}\\\\7.1x10^{-4}=\frac{x^2}{0.02023M-x}$

Next, by solving for the two roots of x, we get:

$x_1=-0.004161M\\\\x_2=0.003451M$

Whereas the correct value is 0.003451 M. Finally, we compute the resulting pH:

$pH=-log(0.003451)\\\\pH=2.462$

Best regards!

4 0

3 years ago

Why does magma in the mantle rise through the crust above it

Natali5045456 [20]

Currents from the lava

4 0

4 years ago

Read 2 more answers

Compounds whose colors are sensitive to pH are best defined as

statuscvo [17]

<span>Compounds whose colours are sensitive to pH are best defined as.......Acid-base indicators.</span>

4 0

4 years ago

In November 1987, a massive iceberg broke loose from the antartic ice mass and floated free in the ocean. The chunk of ice was e

il63 [147K]

<h2>Answer:</h2>

1.58 × 10∧16 pools.

<h3>Explanation:</h3>

Given:

Length of ice berg= 98 miles = 1557716 meters

Width of iceberg = 25 miles = 40233.6 meters

Thickness of iceberg = 750 ft = 230 meters

Volume of water in a swimming pool = 24,000 gallons = 90850 liters

The volume of the ice berg:

Volume = Length . width . thickness

Volume = 1557716 . 40233.6 . 230 = 1,441, 468, 016, 5248 m3 = 1,441, 468, 016, 5248 × 10 ∧3 L.

1 pool contains liters of water: 90850 liters

1,441, 468, 016, 5248 × 10 ∧3 liters contains = 1/90850 . 1,441, 468, 016, 524.8 × 10 ∧3 .

= 1.100 . 1,441, 468, 016, 5248 × 10 ∧3 L.

= 1.58 × 10∧16 pools.

Hence 1.6 × 10∧16 pools will be filled with that chunk of ice.

4 0

3 years ago

1.)Which of the following is an appropriate action if you are caught outside in a thunderstorm?

arsen [322]

Answer:

1) Squat down low and cover your head. (if no shelters are present)

2) 1 gallon per person per day

8 0

3 years ago

Read 2 more answers