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Brrunno [24]
3 years ago
12

Help me how to draw this graphhh??ASAPPPP

Chemistry
1 answer:
Aleksandr [31]3 years ago
7 0

Refer to the attachment

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What law of motion is represented in the description:
Ugo [173]
I think it is 2nd law of motion
7 0
3 years ago
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Which neutral element does the orbital diagram represent?
valentinak56 [21]

Answer:

Silicon

Explanation:

The total of electrons: 2 + 2 + 6 + 2 + 2

In neutral state: #electrons = #protons = 14

so element with atomic number of 14 is silicon

3 0
1 year ago
To which factor can the principles of Nicholas Steno be applied?
Tcecarenko [31]

Answer:

the rock layers of the Grand Canyon

Explanation:

Steno's law are laws that applied to sedimentary rocks. These laws helps in understanding sedimentary sequences.

Sedimentary rocks are derived from the deposition of pre-existing rocks in basins. In order to understand some important relationships between these rock layers, Steno's  law offer a good insight.

Steno's law are often applied when we want to do relative dating of rock layers. Some of the laws are:

  • Law of superposition of strata
  • Law of original horizontality
  • Law of lateral continuity
  • Law of inclusion
  • Law of fossil and fauna succession

These laws helps to interpret sedimentary rock sequences better.

7 0
4 years ago
Read 2 more answers
Please use the below balanced equation to answer this question.    2H2(g)  +  O2(g)  ->   2H2O(l) How many grams of water wil
Blizzard [7]
At STP (standard temperature and pressure conditions), 1 mol of any gas occupies 22.4 L 
This rule is applied to O₂
22.4 L volume occupied by 1 mol
Therefore 83.4 L occupied by - 1/ 22.4 x 83.4 = 3.72 mol
stoichiometry of O₂ to H₂O is 1:2
then the number of moles of water produced - 3.72 mol x 2= 7.44 mol
mass of water produced - 7.44 mol x 18.01 g/mol = 134.1 g
correct answer is D

4 0
3 years ago
40.0% C, 6.72% H, 53.29%, O. Molar mass is 60 g/mol. Determine the empirical and molecular formula.
arsen [322]

Answer:

Molecular formula: C₂H₄O₂

Empirical formula: CH₂O

Explanation:

40 % C, 6.72 % H and 53.29 % O states the centesimal composition of the compound. These data means that in 100 g of compound we have x grams of a determined element.

We divide the mass by the molar mass of each:

40 g / 12 g/mol = 3.33 moles of C

6.72 g / 1 g/mol = 6.72 moles of H

53.29 g / 16 g/mol = 3.33 moles of O

We can determine rules of three to get, the molecular formula.

In 100 g of compound we have 3.33 moles of C, 6.72 moles of H and 3.33 moles of O; therefore in 60 g (1 mol) we must have

- (60 . 3.33) / 100 = 2 moles of C

- (60 . 6.72) / 100 = 4 moles of H

- (60 . 3.33) / 100 = 2 moles of O

Molecular formula is C₂H₄O₂

Empirical formula has the lowest suscripts; we divide by two, so the empirical formula is CH₂O

3 0
3 years ago
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