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Darya [45]
3 years ago
6

Explain the following observation. Treatment of alkyl chloride A with NaOCH2CH3 yields only one product B, whereas treatment of

A with very dilute base in CH3CH2OH yields a mixture of B and C, with C predominating. Select the single best answer.
Chemistry
1 answer:
exis [7]3 years ago
7 0

Answer:

Shifting from concentrated to dilute dilute base switch the mechanism from E2 to E1.

Explanation:

An elimination reaction is known as an organic reaction that involves two substituents being removed from a compound in either one step or two steps mechanism. The one step mechanism is referred to as the E2 (bimolecular elimination) reaction while the two steps mechanism is referred to as the E1 (unimolecular elimination) reaction. In the presence of concentrated base, the mechanism of the reaction is one step mechanism while in the presence of dilute base, the mechanism of the reaction is a two steps mechanism. Therefore, shifting from concentrated to dilute base will automatically switch the mecahnism from E2 reaction to E1 reaction.

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K for enolization of 2,4-cyclohexadienone is about 1013. Explain why the enol is so much more stable than the keto tautomer.
torisob [31]

Answer:

Because the value of K is huge.

Explanation:

The tautomer is a kind of isomer in which exist an equilibrium between a ketone and an enol, or between an aldehyde and an enol. So, in the enolization, the ketone is the reactant and the enol is the product.

The equilibrium reaction can be characterized by an equilibrium constant, which is the ratio of the concentration of the products by the concentration of the reactants.

Because the constant K is extremely large (10¹³) we can conclude that the concentration of the product will be greater than the concentration of the reactant, in the equilibrium. It means that the concentration of the enol will be greater.

So, the ketone is unstable and forms in a great amount the more stable product, the enol.

4 0
3 years ago
A buffer solution is made using a weak acid, HA. If the pH of the buffer is 9 and the ratio of A– to HA is 100, what is the pKa
sdas [7]
To calculate the pKa of the weak acid, we use the Henderson-Hasselbalch equation. It is expressed as pH = pKa - log [HA]/[A-]. This equation takes into account the concentration of the substance that does not dissociates into ions since it is a weak acid. We caculate as follows:

pH = pKa - log [HA]/[A-]
9 = pKa - log 1/100
pKa = 7
3 0
3 years ago
In Experiment 9, a 1.05 g sample of a mixture of NaCl (MW 58.45) and NaNO2 (MW 69.01) is reacted with excess sulfamic acid. The
Kaylis [27]

Answer:

There is 76.6 mL of nitrogen collected

Explanation:

<u>Step 1: </u>Data given

Mass of the sample = 1. 05 grams

The sample is 40.00% by mass NaNO2

MW of NaCl = 58.45 g/mol

MW of NaNO2 = 69.01 g/mol

Temperature = 22.0 °C

Pressure = 750.0 mmHg = (750/760) atm

The vapor pressure of water at 22.0°C is 19.8 mm Hg = 0.02605 atm

<u>Step 2:</u> Calculate mass of NaNO2

(40/100)*1.05  = 0.42 grams

<u>Step 3:</u> Calculate moles of NaNO2

Moles NaNO2 = 0.42 grams / 69.01 g/mol

Moles NaNO2 = 0.00608 moles

<u>Step 4:</u> Calculate moles of N2

For 2 moles of NaNO2 we'll get 1 mol of N2

For 0.00608 moles of NaNO2 we'll get 0.00608/2 = 0.00304 moles

<u>Step 5:</u> Calculate pressure of N2

P = 750.0 - 19.8 = 730.2 mmHg = (730.2/760)atm = 0.96079 atm = 97352 Pa

<u>Step 6:</u> Calculate volume of N2

PV = nRT

⇒ P = the pressure of N2 =  0.96079

⇒ V = the volume of N2 = TO BE DETERMINED

⇒ n = moles of N2 = 0.00304 moles

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 22°C = 295 Kelvin

V = (0.00304*0.08206*295)/0.96079

V = 0.0766 L = 76.6 mL

There is 76.6 mL of nitrogen collected

4 0
4 years ago
What is a chemical change and what is a chemical property? Give Example.
nordsb [41]
Look it up on google
8 0
3 years ago
Read 2 more answers
Lipid-soluble hormones usually bind to __________ receptors.
kumpel [21]

Answer:...intercellular receptors

Explanation:

Lipophilic hormone also known as lipid-soluble hormones can pass through the cell's plasma membrane, to bind to intracellular receptors, so as to effect change in gene expression.

3 0
4 years ago
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