Question

XY=4n+3,YZ=2n-7,XZ=22

Answer 1

Choose one of the equations, then try and rewrite in terms of 1 Unknown, eg I've chosen XZ= 22 and am going to write it in terms of X

XZ = 22
Z = 22/X (this is writing Z in terms of X)
So... X(22/X)= 22
22/X=22X
22 = 22X^2 (* ^2 is to the power 2)
Therefore X = 1
And Z= 22

Use this to solve the remaining equations

1xY = 4n + 3
22Y= 2n - 7
Then rearrange and do simultaneous equations

22Y - 66 = 88n
22Y + 7 = 2n
-73 = 86n
n = -73/86

It is very very likely that I have made a mistake somewhere here given the strange number I have for n but I spent far too long on this not to post it ahaha, even if the numbers are incorrect this is the general method I would follow