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insens350 [35]
3 years ago
12

Figure 2 was constructed using figure 1. For the transformation to be defined as a rotation, which statements must be true? Sele

xt three options.
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

The segment connecting the center of rotation, C, to a point on the pre-image (figure 1) is equal in length to the segment that connects the center of rotation to its corresponding point on the image (figure 2).

The transformation is rigid.

Every point on figure 1 moves through the same angle of rotation about the center of rotation, C, to create figure 2.

If figure 1 is located 360° about point C, it will be mapped onto itself.

Step-by-step explanation:

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You invest 900 in an account that pays a interest rate 05 5.5% , compunded countinuously.
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4 0
3 years ago
Help. Algebra rjsffjdnsifvnswkfnc
jek_recluse [69]

Answer:

No x-intercept/Zero

Step-by-step explanation:

f(x)=3x(3/4)x-4

To find x-intercept/zero, substitute f(x)=0

0=3x(3/4)x-4

To raise a fraction to a power, raise the numerator and denominator to that power

0=3x 3 x-4/4 x-4

Calculate the product

0=3 x-3/4 x-4

Since the right-hand side is always positive, the statement is false for any value of x

Since there is no solution for f(x)=0, there is no x-intercept/Zero  

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3 years ago
HELP ASAP!!<br> please show work!!!<br> what is the value of x in the matrix equation below?
son4ous [18]

Answer:

x=2

Step-by-step explanation:

The given matrix equation is ;

\frac{3}{2}\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y \left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]

We multiply the scalars to get;

\left[\begin{array}{cc}\frac{3}{2}x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]

We simplify to get;

\left[\begin{array}{cc}\frac{3}{2}x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]

By the equality property of matrices, we can write the following equations;

\frac{3}{2}x+y=z...(1)

6+2y=2

2y=2-6

2y=-4

y=-2

Also;

12+3y=6z

\Rightarrow 12+3(-2)=6z

\Rightarrow 12-6=6z

\Rightarrow 6=6z

\Rightarrow z=1

We substitute these values into equation (1) to find x.

\frac{3}{2}x-2=1

\frac{3}{2}x=1+2

\frac{3}{2}x=3

\frac{1}{2}x=1

x=2

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vovikov84 [41]

Answer:

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Step-by-step explanation:

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I hope I can show the image, but I hope this may help you, the answer is:

The center of the inscribed circle of ΔABC is <u>point S</u> , and the center of the circumscribed circle of ΔABC is <u>point P.</u>
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4 years ago
Read 2 more answers
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