Answer:A
Step-by-step explanation:
the answer is A
The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
<h3>Equation of a line</h3>
A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;
y - y1 = -1/m(x-x1)
where
m is the slope
(x1, y1) is the intercept
Given the following
Point = (4, -1)
Line: 2x-y - 7 = 0
Determine the slope
-y = -2x + 7
y= 2x - 7
Slope = 2
Substitute
y+1 = -1/2(x -4)
Write in slope-intercept form
2(y + 1) = -(x - 4)
2y+2 = -x + 4
2y = -x + 2
y = -1/2 + 1
Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
Learn more on equation of a line here: brainly.com/question/13763238
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Answer:
Option D
Step-by-step explanation:
We have to find the value of the composite function (h o k)(2).
Since, (h o k)(x) = h[k(x)]
(h o k)(2) = h[k(2)]
From the picture attached,
At x = 2
k(2) = (-2)
Therefore, h[k(2)] = h(-2)
Since, h(x) = 
Therefore, h(-2) = 
= -3
(h o k)(2) = -3 is the answer.
Option (D) is the correct option.
Answer: The correct answer is March and September
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