The product of this is 90
Answer:
90.67% probability that John finds less than 7 golden sheets of paper
Step-by-step explanation:
For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.
This means that 
14 of these containers of paper.
This means that 
What is the probability that John finds less than 7 golden sheets of paper?

In which









90.67% probability that John finds less than 7 golden sheets of paper
Answer:
diameter = 3,600 units
Step-by-step explanation:
Let
= 3.14
C = 2
r
11,304 = 2(3.14)r
r = 1,800
d = 2r = 2(1,800) = 3,600
Answer:
Vertical stretch of factor of 3
translated to the right 2
translated up 5
Step-by-step explanation:
- The sample size is 64.
- The point estimate of the population proportion is 0.625.
-The margin of error is approximately 16%.