Answer:
Guessing 8 games correctly is an unusual outcomes, significantly better than just guessing, which means tht Paul has psychic powers
Step-by-step explanation:
For each game, there are only two possible outcomes. Either Paul guesses the winner correctly, or he does not. The probability of guessing the winner of a game is independent of other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
![E(X) = np](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np)
The standard deviation of the binomial distribution is:
![\sqrt{V(X)} = \sqrt{np(1-p)}](https://tex.z-dn.net/?f=%5Csqrt%7BV%28X%29%7D%20%3D%20%5Csqrt%7Bnp%281-p%29%7D)
Outcomes that are more than 2.5 standard deviations from the mean are considered unusual.
Paul guesses one team out of two.
So ![p = 0.5](https://tex.z-dn.net/?f=p%20%3D%200.5)
Eight games
So ![n = 8](https://tex.z-dn.net/?f=n%20%3D%208)
1 Does Paul have psychic powers? In other words, is an 8 for 8 record significantly better than just guessing?
Let's find if 8 is an unusual outcomes.
![E(X) = np = 8*0.5 = 4](https://tex.z-dn.net/?f=E%28X%29%20%3D%20np%20%3D%208%2A0.5%20%3D%204)
![\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{8*0.5*0.5} = 1.41](https://tex.z-dn.net/?f=%5Csqrt%7BV%28X%29%7D%20%3D%20%5Csqrt%7Bnp%281-p%29%7D%20%3D%20%5Csqrt%7B8%2A0.5%2A0.5%7D%20%3D%201.41)
Guessing 6 or more games correctly are unusual outcomes.
Guessing 8 games correctly is an unusual outcomes, significantly better than just guessing, which means tht Paul has psychic powers