Question

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Answer 1

The sum of the inner angles of a polygon with n sides is $180(n-2)$

Since your polygon has 6 sides, the sum of its inner angles has to be

$180(6-2) = 180 \cdot 4 = 720$

On the other hand, the sum of its inner angles is

$75+132+113+108+160+x = 588+x$

And it has to be 720, so we have

$588+x=720 \iff x = 720-588 = 132$