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abruzzese [7]
3 years ago
6

Write the equation of the line that passes through (−1, 5) and has a slope of 3 in point-slope form. (2 points)

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0
-1 = 3(5) + b
-1 = 15 + b
-16 = b

y = 3x -16
y - 5 = 3(x +1)
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geniusboy [140]
<span>Remember that it's against our guidelines to copy content from other websites, books or any other material to which you don't own the rights to. We know you have the power to solve these problems on your own</span>
4 0
3 years ago
Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths
kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment


Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

Evaluate the sum

h^2 = 169

Evaluate the exponent of both sides

h = 13

The cosine ratio is then calculated as:

cos(L) = KL/h

This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

3 0
2 years ago
12e^5 divide by 3e^3
Paladinen [302]

The answer would be <em>29.5562243957</em>.

5 0
3 years ago
The distance Max's bike moves is directly proportional to how many rotations his bike's crank shaft has
Gemiola [76]

Answer:

187.5 feet

Step-by-step explanation:

we know that

Max's bike moves 25 feet after two rotations

so

using proportion

Find out how many feet will the bike move after 15 rotations

Let

x ----> the distance in feet

\frac{25}{2}\frac{ft}{rev}=\frac{x}{15}\frac{ft}{rev}\\\\x=15(25)/2\\\\x=187.5\ ft

7 0
3 years ago
Read 2 more answers
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
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