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abruzzese [7]
3 years ago
6

Write the equation of the line that passes through (−1, 5) and has a slope of 3 in point-slope form. (2 points)

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0
-1 = 3(5) + b
-1 = 15 + b
-16 = b

y = 3x -16
y - 5 = 3(x +1)
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maxonik [38]

Answer: y = \frac{1}{5}x + 8

Step-by-step explanation:

       This is asking us to remove the parameter. In other words, we want an equation with only the relation between x and y, so we need to remove the t. There are a few ways to do this, but I am going to set one equation equal to t and then plug it into the next one.

     Given:

x = 5t

    Divide both sides of the equation by 5:

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     -

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    Plug in:

y = (\frac{1}{5}x) + 8

    Answer:

y = \frac{1}{5}x + 8

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Find the magnitude of a vector with initial point A(3, 4, 10) and terminal point B(8, 4, –2).
Fantom [35]

Answer:

B

Step-by-step explanation:

Use the distance formula in 3 dimensions

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2      }

with (x₁, y₁, z₁ ) = (3, 4, 10) and (x₂, y₂, z₂ ) = (8, 4, - 2)

d = \sqrt{(8-3)^2+(4-4)^2+(-2-10)^2}

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gregori [183]

Answer:

Yes

Step-by-step explanation:

If you replace each x with -3 and each y with 2 you get:

1) 2<-4*(-3)

2<12

True

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13>7

True

Therefore the point is part of the solution set

7 0
3 years ago
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