Sec^2x-tan x-3 = RED IS SUS
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
18+30=48
48+40=88
88+40=128
128+50=178
Thats all i found so far in the pattern
30,40,40,50
then it drops
by 140 then adds by 30..
I dont know how else to explain it
Given that <span>Li
is making beaded necklaces for each necklace, she uses 27 spacers, plus
5 beads per inch of necklace length.
The equation to find how many
beads Li needs for each necklace can be obtained as follows:
A. The input variable is the number of inches of the necklace length (x).
B. The output variable is the number of beads Li needs for each necklace (y).
C. The required equation is given by
y = 5x</span>
