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4 years ago

the length of one side of an equilateral triangle is 6 square root of 3 meters. findbthe length of one altitude of the triangle

Mathematics

1 answer:

shutvik [7]4 years ago

5 0

6 to the square root of 3 is basically 6 x 6 x 6 so the length of one side is
216 meters

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According to a Yale program on climate change communication survey, 71% of Americans think global warming is happening.† (a) For

SpyIntel [72]

Answer:

a) 0.2741 = 27.41% probability that at least 13 believe global warming is occurring

b) 0.7611 = 76.11% probability that at least 110 believe global warming is occurring

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$p = 0.71$

(a) For a sample of 16 Americans, what is the probability that at least 13 believe global warming is occurring?

Here $n = 16$ , we want $P(X \geq 13)$ . So

$P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 13) = C_{16,13}.(0.71)^{13}.(0.29)^{3} = 0.1591$

$P(X = 14) = C_{16,14}.(0.71)^{14}.(0.29)^{2} = 0.0835$

$P(X = 15) = C_{16,15}.(0.71)^{15}.(0.29)^{1} = 0.0273$

$P(X = 16) = C_{16,16}.(0.71)^{16}.(0.29)^{0} = 0.0042$

$P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) = 0.1591 + 0.0835 + 0.0273 + 0.0042 = 0.2741$

0.2741 = 27.41% probability that at least 13 believe global warming is occurring

(b) For a sample of 160 Americans, what is the probability that at least 110 believe global warming is occurring?

Now $n = 160$ . So

$\mu = E(X) = np = 160*0.71 = 113.6$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{160*0.71*0.29} = 5.74$

Using continuity correction, this is $P(X \geq 110 - 0.5) = P(X \geq 109.5)$ , which is 1 subtracted by the pvalue of Z when X = 109.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{109.5 - 113.6}{5.74}$

$Z = -0.71$

$Z = -0.71$ has a pvalue of 0.2389

1 - 0.2389 = 0.7611

0.7611 = 76.11% probability that at least 110 believe global warming is occurring

3 0

3 years ago

Jeremy wants to determine the number of solutions for the equation below without actually solving the equation.

Degger [83]

Answer:

1 solution

Step-by-step explanation:

Jeremy can simplify the equation enough to determine if the x-coefficient on one side of the equation is the same or different from the x-coefficient on the other side. Here, that simplification is ...

-3x -3 +3x = -3x +3 +3

We see that the x-coefficient on the left is 0; on the right, it is -3. These values are different, so there is one solution.

In the attached, the left-side expression is called y1; the right-side expression is called y2. The two expressions are equal where the lines they represent intersect. That point of intersection is x=3. (For that value of x, both sides of the equation have a value of -3.)

Additional comment

If the equation's x-coefficients were the same, we'd have to look at the constants. If they're the same, there are an infinite number of solutions. If they are different, there are no solutions.

8 0

3 years ago

Read 2 more answers

Alina spent no more than $45 on gas for a road trip. The first gas station she used charged $3.50 per gallon and the second gas

xenn [34]

The answer is C.Your welcome

5 0

3 years ago

Read 2 more answers

How do you decompose 1 1/4

uysha [10]

There are 4 EQUAL pieces.

To build 1 whole you must add together 4 pieces or compose the fraction with all four pieces 1/4 + 1/4 + 1/4 + 1/4 = 4/4 or 1 whole.

8 0

3 years ago

Read 2 more answers

A researcher collects data on the number of times race horses are raced during their careers. The veterinarian finds that the av

vesna_86 [32]

Answer:

95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

Step-by-step explanation:

Explanation:-

The veterinarian finds that the average number of races a horse enters is 15.3

The mean of the sample x⁻ = 15.3

Given standard deviation of the sample 'S' = 6.8

Given sample size 'n' = 25

Degrees of freedom = n-1 =25-1 =24

The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance

95% confidence for µ, the average number of times a horse races

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$

$(15.3- 2.064 \frac{6.8}{\sqrt{25} } , 15.3 + 2.064\frac{6.8}{\sqrt{25} } )$

(15.3 - 2.80704 ,15.3 +2.80704)

(12.493 , 18.107)

Conclusion:-

95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

3 0

3 years ago