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balandron [24]
3 years ago
15

If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is

Mathematics
2 answers:
yuradex [85]3 years ago
7 0
1,2,3,7
I believe the range is just depending on your y values,and since an equation is not given your range should just be the y values of that set
son4ous [18]3 years ago
3 0

I think this should help :-)

1. The points that are in given in the (x, y) form aka (x-coordinate, y-coordinate).

2. The range is the set of values onto which ƒ sends the x's.


The x's are sent the numbers 1, 2, 3, 1, 7 which ends up looking like {1,2, 3, 7}

So the answer is {1,2,3,7}

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Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

6 0
3 years ago
In a particular game, a fair die is tossed. If the number of spots showing is either four or five, you win $1. If the number of
TiliK225 [7]

Answer:

The probability that you win at least $1 both times is 0.25 = 25%.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either you win at least $1, or you do not. Games are independent. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of winning at least $1 on a single game:

The die has 6 sides.

If it lands on 4, 5 or 6(either of the three sides), you win at least $1. So

p = \frac{1}{2} = 0.5

You are going to play the game twice.

This means that n = 2

The probability that you win at least $1 both times is

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.5)^{2}.(0.5)^{2} = 0.25

The probability that you win at least $1 both times is 0.25 = 25%.

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