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3 years ago

Plz help me with the work. i have the answer

Mathematics

2 answers:

kotegsom [21]3 years ago

8 0

OptionA is the answer

maxonik [38]3 years ago

6 0

Add/subtract likenesses here (only one though)

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A glassblower can produce a set of simple glasses in about 2 h. When the glassblower works with an apprentice, the job takes abo

Snowcat [4.5K]

Answer:

6 hours.

Step-by-step explanation:

Let t represent the time taken by apprentice in hours to make a set of glasses when working alone.

Part of work completed by apprentice in one hour would be $\frac{1}{t}$ .

We have been given that a glassblower can produce a set of simple glasses in about 2 hours. So part of work completed by glassblower in one hour would be $\frac{1}{2}$ .

While working together, the job takes about 1.5 hours. So part of work completed by both in one hour would be $\frac{1}{1.5}$ .

Now we will equate sum of work competed by both in hour by work completed by both working together is one hour as:

$\frac{1}{t}+\frac{1}{2}=\frac{1}{1.5}$

$\frac{1}{t}\cdot 3t+\frac{1}{2}\cdot 3t=\frac{1}{1.5}\cdot 3t$

$3+\frac{3}{2}\cdot t=\frac{3t}{1.5}$

$3+1.5\cdot t=2t$

$3+1.5t-1.5t=2t-1.5t$

$3=0.5t$

$\frac{3}{0.5}=\frac{0.5t}{0.5}$

$6=t$

Therefore, it will take 6 hours for the apprentice to make a set of glasses when working alone.

7 0

3 years ago

Simplify:4x+6(3x-12 A 10x -12 B18x-12 C22x-12 D30*30X-12

olya-2409 [2.1K]

4x+6 (3x ) - 12 = 4x +6 *3 x - 12
= 4x +18 x - 12
= 22 x -12

8 0

3 years ago

How do you figure out the area of a triangle?

andrew11 [14]

General formula for area of triangle is $A=\frac{h_bb}{2}$ .

Where:

$h_b$ is height of triangle perpendicular to base side of triangle.
$b$ is the length of base side of triangle.

Multiplying $h_b$ and $b$ results in rectangle, dividing that by 2 gives you area of a triangle.

Hope this helps.

5 0

3 years ago

Read 2 more answers

I need help with this one

grigory [225]

Answer:

The first three

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The graph of a linear function passes through the points (2, 4) and (8, 10).

Keith_Richards [23]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 2}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ 8}}\quad ,&{{ 10}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{10-4}{8-2}$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=2\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}$

8 0

3 years ago