Subtract 8p from 9p and then rewrite the equation. Then you add 7 to 4 and rewrite the equation again. Then you divide 1p by 11 and get p=11.
        
             
        
        
        
6) 1.6 x 10^-4 = 0.00016
7) diameter of the sun
8) water molecule 
9) grain of salt
        
             
        
        
        
Let your 1st integer be X, then the 2nd will be (X+1) and the 3rd will be (X+2). Since we need the sum of the squares to equal 110 ⇒ X² + (X+1)² + (X+2)² = 110 Expanding the left-hand side: X² + X² + 2·X + 1 + X² +4·X + 4 = 110 3·X² + 6·X + 5 = 110 3·X² + 6·X - 105 = 0 Solve using the quadratic formula and you get roots: X = 5, X = -7 Your problem doesn't state that we have to restrict the solution to positive integers only and since we are summing the squares we have 2 solutions that work: 5, 6, 7 and -7, -6, -5
        
             
        
        
        
F(x)/(x-a)=f(a)
Here a=4
So we need f(4)
F(4)=(4)^3 -1
F(4)=64-1=63
        
             
        
        
        
Answer:
$7
Step-by-step explanation:
4 x 39 = 156 
156 - 149 = 7