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3 years ago

Plz help plzplzplzplz

Mathematics

2 answers:

marissa [1.9K]3 years ago

8 0

Answer:

Please refer to the attachment

astraxan [27]3 years ago

4 0

Answer:

x = -1/2 or x = -3

Step-by-step explanation:

2x^2 + 7x + 3 = 0

First, we try factoring the polynomial.

(2x + 1)(x + 3) = 0

It works. Now we set each factor equal to zero.

2x + 1 = 0 or x + 3 = 0

2x = -1 or x = -3

x = -1/2 or x = -3

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3. The picture below shows a relationship between the number of circles and triangles.

dimaraw [331]

Answer:

D or A

Step-by-step explanation:

(D) One circle : four triangles

Example:

One triangle is 1/4 of a circle

(A) One circle : four triangles

Example:

If there is two circles, the triangles will double like it shows [evidences]

6 0

3 years ago

Triangle P R Q is shown. The length of side P R is 5 n. The length of side R Q is 32 + n. Angles R P Q and P Q R are congruent.

snow_tiger [21]

Answer:

Step-by-step explanation:

According to Triangle P R Q, if angles R P Q and P Q R are congruent, this means that two of the sides of the triangle a re also congruent (Isosceles triangle).

We can say then that length of side PR is equal to that of RQ i.e PR = RQ

Given

PR = 5n

RQ = 32+n

Required

Length of PR

Since the two sides are equal i.e PR = RQ

5n = 32+n

5n - n = 32

4n = 32

n = 32/8

n = 4

Get PR;

Since PR = 5n

PR = 5(4)

PR = 20

Hence the length of PR is 20.

6 0

3 years ago

Read 2 more answers

Pls answer 13 b ill mark u brainlist

gladu [14]

Answer:

7 students

Step-by-step explanation:

1+2+4=7students

5 0

3 years ago

Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

*<br> What is the circumference?<br><br> 16 in

BlackZzzverrR [31]

Answer:50.27

Step-by-step explanation:

5 0

3 years ago

Plz help plzplzplzplz​

Plz help plzplzplzplz