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Ivan
2 years ago
12

What’s (7(123456.789)4)0 but the 4 and 0 at the end are exponents

Mathematics
1 answer:
IrinaK [193]2 years ago
8 0

Answer:

7123456.789^{40} = 1.281244e+274

Step-by-step explanation:

I have NO IDEA if that helps,... BUT I hope it does,... Chow,...!

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Answer:

x = -2

Step-by-step explanation:

Solve for x:

(2 (3 x - 4))/5 = -4

Multiply both sides of (2 (3 x - 4))/5 = -4 by 5/2:

(5×2 (3 x - 4))/(2×5) = -4×5/2

5/2×2/5 = (5×2)/(2×5):

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5/2 (-4) = (5 (-4))/2:

(5×2 (3 x - 4))/(2×5) = (-4×5)/2

(5×2 (3 x - 4))/(2×5) = (2×5)/(2×5)×(3 x - 4) = 3 x - 4:

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5 (-2) = -10:

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Add 4 to both sides:

3 x + (4 - 4) = 4 - 10

4 - 4 = 0:

3 x = 4 - 10

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3 x = -6

Divide both sides of 3 x = -6 by 3:

(3 x)/3 = (-6)/3

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Answer:  x = -2

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