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2 years ago

12

What’s (7(123456.789)4)0 but the 4 and 0 at the end are exponents

1 answer:

IrinaK [193]2 years ago

8 0

Answer:

$7123456.789^{40}$ = 1.281244e+274

Step-by-step explanation:

I have NO IDEA if that helps,... BUT I hope it does,... Chow,...!

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Which of the following sets shows all the numbers from the set {1, 2.5, 3, 4.5, 5} that make the inequality 3a + 4 ≥ 13 true?

zmey [24]

3(1)+4<span>≥ 13
7</span><span>≥ 13
No

3(2.5)+4</span><span>≥ 13
11.5</span><span>≥ 13
No

3(3)+4</span><span>≥ 13
13</span><span>≥ 13
Yes

{3, 4.5, 5}</span>

3 0

3 years ago

Read 2 more answers

A baby elephant weighs 1,400 pounds, which is 7,437 pounds less than her mother. Write an equation to express the weight of the

erica [24]

Let's say that y is the weight of the mother and x is the weight of the baby.
We know that the baby is 7437 pounds less than the mother, which means you need to add 7437 pounds to the baby's weight to get the mother's.
We can show it like this:
x+7437=y.
We know what the baby's weight is (1400 lbs), so just sub it in:
1400+7437=y
y=8837 lbs
The mom weighs 8837 pounds.

4 0

3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

Sarah and Jean were able to sell 4 dozen of cupcakes in a hour at a school fair if this rate continue how many dozen s of cupcak

Alik [6]

Answer:

Step-by-step explanation:

Firstly,

We can tell by reading the question that they sell 48 cupcakes witch is 4 dozens every hour so if they continue to sell at that same rate then:

There are 8 hours between 9am and 5pm

∴ It is 48:1

That means 48 cupcakes per hour this is equation is a direct proportion so if any number increases so will the other

So if it is 48:1 then x:8 with be = 48x8

∴ Sarah and Jean will be able to sell 384 cupcakes

7 0

2 years ago

Thomas is running for class president. e can have a campaign buttons made for a one-time fee of $23.60,plus $0.50 for each butto

mariarad [96]

Lets x = <span>number of buttons
</span><span>
Equation:
0.50x + 23.60 = 257
0.50x = 233.4
x = 466.8

Maximum number of buttons = 466

Answer:
</span><span>D) 466 buttons</span>

3 0

2 years ago

Read 2 more answers