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mixas84 [53]
2 years ago
10

Describe how to compare the two ratios 5:8 to 7:9. Tell each step to set up the ratios, then explain what to do to be able to co

mpare the ratios. Finally make sure to answer how the ratios compare. ~ 100 POINTS AND ILL GIVE YOU BRAINLIEST IF YOU ANSWER CORRECTLY AND 5 SENTENCES NEEDED
Mathematics
2 answers:
Lady_Fox [76]2 years ago
7 0

Steps:-

  • First rewrite
  • Then convert to fractions
  • Then divide both

\\ \rm\rightarrowtail 5:8::7;9

\\ \rm\rightarrowtail 5/8:7/9

\\ \rm\rightarrowtail \dfrac{5(9)}{8(9)}:\dfrac{7(8)}{9(8)}

\\ \rm\rightarrowtail \dfrac{45}{72}:\dfrac{56}{72}

\\ \rm\rightarrowtail \dfrac{45}{56}

  • Second one is bigger
lutik1710 [3]2 years ago
3 0

Answer:

5/8 is smaller.

Step-by-step explanation:

A ratio is just a different type of fraction, a 5:8 ratio means 5/8 which is 0.625. A 7:9 ratio equals 7/9 which is 0.777777

Then to compare them you see which is smaller or bigger.

0.77777  is bigger than 0.625 so we know that 0.77777777 which was the 7:9 ratio is the bigger one.

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he initial number of trees was 204.

<h3>How to find the initial number of trees?</h3>

The first step to finding the initial number of trees is to write an equation that represents the situation.

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  • 5 trees were removed = t - 5
  • Each tree produces 210 oranges = (t-5) (210)
  • The total of oranges is 41,780 = (t-5) (210)= 41,780

  • Solve the equation:

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  • t-5= 41,780 / 210
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This number can be rounded as 204.

Note: This question is incomplete; here is the missing section:

Find the initial number of trees.

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Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

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Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

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