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inessss [21]
3 years ago
7

If UV = KL and KL = 6, then UV = 6

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
Yeah u r absolutely right
Igoryamba3 years ago
4 0
Yes thats correct because they all equal eachother Ur right
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A race car is driven around a circular track at a constant speed of 180mph. If the diameter is 1/2 mile, what is the angular spe
Bogdan [553]
If the diameter is 1/2 mile, that is 0.5 mile, then the radius is 0.25 -half of it!

the angular speed is theta/time, which means

 w=theta/time

but another formula for it is Velocity*radians

w=velocity*radians

velocity is 180 mph and radians are (revolution/2\pi radius), that is:

w=180*(1/2\pi*0.25)
and if we calculate this, we have: w=114.59, which is the correct answer!
4 0
3 years ago
Part 1.] Does the graph have even symmetry, odd symmetry, or neither?
QveST [7]
Part 1
The graph has even symmetry.  You can see that because it is symmetric with respect to the y-axis.
Functions that have even symmetry have the following property:
f(x)=f(-x)
Part 2
To answer this we can simply check if the property we mentioned earlier holds for this function.
sin(\frac{\pi}{2})\ne sin(-\frac{\pi}{2})
We can see that sine does not have even symmetry. 
In fact, sine function has the following property: 
sin(x)=-sin(x)
This is called odd symetry.
Part 3
Take a look at the function that you attached in the picture. We know that function has even symmetry. 
Reflection over x-axis and <span>180° rotation around the origin would give us -f(x). We would not end up with the same function, so these two are out. 
</span><span>90° rotation around the origin would mean we swapped x <span>and y</span> so that one is out too. R</span><span>eflection over the line y=x is a property of functions that have an odd symmetry.
We are left with reflection around y-axis and, as mentioned before, this is the property of evenly symmetric functions.</span>
4 0
3 years ago
1. When the discriminant is grater than zero, the equation has:
Yakvenalex [24]
No spoliation skdnfnd
3 0
3 years ago
Can somebody help me with this question !​
Pavlova-9 [17]

Answer:

No please! Mr excuse me I am not your type bye

3 0
3 years ago
The base of a solid in the first quadrant of the xy plane is a right triangle bounded by the coordinate axes and the line x + y
Ivahew [28]

The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is 

(x - x^2)^2 * sqrt(3)/4. 

Integrating from x = 0 to x = 1, we have 

[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4 

= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144. 

Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...

8 0
3 years ago
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