We can't write the product because there is no common input in the tables of g(x) and f(x).
<h3>Why you cannot find the product between the two functions?</h3>
If two functions f(x) and g(x) are known, then the product between the functions is straightforward.
g(x)*f(x)
Now, if we only have some coordinate pairs belonging to the function, we only can write the product if we have two coordinate pairs with the same input.
For example, if we know that (a, b) belongs to f(x) and (a, c) belongs to g(x), then we can get the product evaluated in a as:
(g*f)(a) = f(a)*g(a) = b*c
Particularly, in this case, we can see that there is no common input in the two tables, then we can't write the product of the two functions.
If you want to learn more about product between functions:
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<h3>
Answer: 2</h3>
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Explanation:
The function f(x) = -4x+1 is the same as y = -4x+1 where y = f(x)
Compare this to y = mx+b and we see the slope here is m = -4
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Now let's find the slope of g(x)
use the slope formula with any two rows you want. I'll pick on the last two rows.
m = (y2-y1)/(x2-x1)
m = (21-9)/(3-1)
m = 12/2
m = 6 is the slope of g(x)
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From here, we add the two slope values
(slope of f)+(slope of g) = -4+6 = 2
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
<span>Step 1: 0.46 = 46⁄100</span>
<span>Step 2: Simplify 46⁄100 = 23⁄50</span><span> hope this helped u</span>
Answer:
it’s because 0.50 is half of 100 and 1/2 is a reduced fraction of 50/100.
Step-by-step explanation:
