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3 years ago

True or false, there is no solution to the systems of inequalities shown below

Mathematics

2 answers:

miss Akunina [59]3 years ago

8 0

False
Because if you plot a graph to both the equation as i have attached the image.. you can see there can be multiple solution to the above system of inequalities.

WARRIOR [948]3 years ago

4 0

False.
there are solutions to this system of inequalities.
-> For a quick check you can take random x, e.g. consider x=0, and substitute it   in the inequality, which gives
  y<5 and y>4 .
  there are infinite number of y satisfying these conditions.
-> You can solve it graphically to get exact solution. draw the line y=3x+5 and y = -x+4. The common region, below y=3x+5 and above y=-x+4 , is the solution for the system of inequalities.

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2 years ago

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2 years ago

Read 2 more answers

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

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2 years ago

A basketball player completed 44.2% of his field goals in the most recent season. He made 287 field goals. How many did he att

Andrej [43]

44.2%= 287

Let the total attempt = x

(287/x) ×100 = 44.2

287/x = 44.2/100

287/x = 0.442

x = 287/0.442

Hope this will help...

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castortr0y [4]

Answer:

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Step-by-step explanation:

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3 years ago