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tangare [24]
2 years ago
7

A cell phone plan charges a $30 activation fee plus $19.50 a month. If Ellie has a maximum of $200 to spend, how many months of

the cell phone plan can she afford?​
Mathematics
2 answers:
Ilya [14]2 years ago
6 0
She can afford a total of 8 full months
qaws [65]2 years ago
5 0

Answer: 3 months

Step-by-step explanation: if you had $30 + $19.50

you get 49.50 if you add 49.50+ 49.50 you get 99.00 add another 49.50 you get 148.50 add another 49.50 you get 198 and you cant keep going

49.50= the total for 1 month

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Abigail jogged 10.6 miles in 2.5 hours. What is her jogging speed in miles per hour? A. 4.32 miles/hour B. 4 miles/hour C. 4.24
Lelechka [254]

do miles/hour =

10.6 miles/2.5 hours =

10.6/2.5 =

4.24 miles/hour


5 0
3 years ago
Read 2 more answers
I am stuck. Please help.
natulia [17]

Answer:

the first one: 24.8

the second one: 2012

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2 years ago
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Silas is starting a lawn mowing company. He determines the start up cost to purchase law mowers is $560. He figures each law wil
Lelechka [254]

Answer:

$1 x $560 =$560

Step-by-step explanation:

3 0
2 years ago
Tom rented a truck for one day. There was a base fee of 19.95 , and there was an additional charge of 85 cents for each mile dri
Sidana [21]

Answer:

231 miles.

Step-by-step explanation:

Tom rented a truck with a base fee of 19.95. You will subtract this from the total since you just want to get the mileage.

Tom is getting charged .85 cents per mile driven.

Tom payed 216.30 subtotal minus the 19.95 base fee since we are trying to only see how many miles he drove.

(216.30-19.95=196.35) This will be total for each mile. All we need to do is divide to get the total of miles

(196.35÷.85= 231)

231 is the number of miles Tom drove.

4 0
2 years ago
Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
2 years ago
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