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ivanzaharov [21]
2 years ago
9

HELPP PLSSS FOR BRAINLEST AND EXTRA POINTS

Mathematics
2 answers:
Damm [24]2 years ago
8 0
C. The cost of a pizza with no toppings is six dollars.
Ede4ka [16]2 years ago
6 0

Answer: B.) <em>The cost of a pizza with no toppings is $6 </em>

Step-by-step explanation:

<em>The y-intercept shown on the graph is (0,6)</em>

<em>Meaning with 0 toppings, the pizza cost </em><em>$6</em>

You might be interested in
What are he square roots of 36/100?
tiny-mole [99]
The square root of 36/100 is c. -6/10 and 6/10
You can get this by using a calculator.
@[email protected]
4 0
2 years ago
Fernando loves to make music playlists. He likes to keep the same ratio of country songs to rock songs. On his summer playlist,
Ede4ka [16]

Answer:

There are 6 rock songs on Fernando's road trip playlist.

Step-by-step explanation:

Given that he keeps the ratio same

This means that the ratios for both summer playlist and trip playlist will be the same

Let

c1 be the country songs in summer playlist

r1 be the rock songs in trip playlist

Similarly,

c2,r2 will be the country and rock songs in trip playlist

Both will be equal so

\frac{c_1}{r_1} = \frac{c_2}{r_2}

Putting the values

\frac{100}{24} = \frac{25}{r_2}\\100r_2 = 25*24\\100r_2 = 600r_2 = \frac{600}{100}\\r_2 = 6

Hence,

There are 6 rock songs on Fernando's road trip playlist.

3 0
3 years ago
The price of 41gram apple is 10.25 rupees.then how many rupees for 1 kg apple​
Elenna [48]

Answer:

1kg apple for 0.25 rupees

Step-by-step explanation:

Hope this helps!!

7 0
2 years ago
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the larg
katovenus [111]
Problema Solution

You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?

Answer provided by our tutors

Make a drawing and denote:


x = half of the length of the enclosure


2x = the length of the enclosure


y = the width of the enclosure


P = 800 ft the perimeter


The perimeter of the two enclosures can be expressed P = 4x + 2y thus


4x + 3y = 800


Solving for y:

........

click here to see all the equation solution steps

........

y = 800/3 - 4x/3


The area of the two enclosure is A = 2xy.


Substituting y = 800/3 - 4x/3 in A = 2xy we get


A = 2x(800/3 - 4x/3)


A =1600x/3 - 8x^2/3


We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum: 


x max = -b/2a, a = (-8/3), b = 1600/3


x max = (-1600/3)/(2*(-8/3))


x max = 100 ft


y = 800/3 - 4*100/3


y = 133.33 ft


2x = 2*100


2x = 200 ft

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
2 years ago
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