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Evgen [1.6K]
3 years ago
9

Given p (x) = 5x - 6 what is the value of p ( 2/5)Help me please quick!​ please

Mathematics
1 answer:
cluponka [151]3 years ago
8 0

Answer:

p(2/5)=-4

Step-by-step explanation:

Plug in 2/5 for x

p(2/5)=5(2/5)-6

Combine like terms

p(2/5)=2-6

p(2/5)=-4

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16. Devon answered 23 out of 25 problems on a math test correctly. What percent of the problems did Devon answer correctly?​
timofeeve [1]

Answer:

92%

Step-by-step explanation:

100/25= 4

4 x 23 = 92

6 0
3 years ago
PLEASE ANSWER ASAPPPP I WILL GIVE BRAINLY!!!!!!!!!!!
Crank

Answer:

-\frac{7}{8}(-\frac{8}{7})x-\frac{3}{4}=20\left(-\frac{8}{7}\right)

the last one

6 0
3 years ago
Read 2 more answers
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
3 years ago
Mrs. B. & Ms. H. each had a repair made on their cars. The initial cost of each repair is $500. Mrs. B. uses a $75 off the r
Elza [17]
Ms.H paid less in fact she paid $22.5 less
7 0
3 years ago
Read 2 more answers
Combine these two like terms to create an equivalent expression: 4z - (-3z)
stealth61 [152]

Answer:

Step-BYU-step explanation

4z - (-3z) = 4z + 3z = 7z

7 0
3 years ago
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