Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
<h2>x = -4 or x = -2</h2>
Step-by-step explanation:
Answer:
10
Step-by-step
Reduce to and simply subtract.
Answer:
h= -8/3
Picture Explanation:
- Divide 3 on both sides of the equal sign, as shown above, so (h) can be alone.
- Since negative 8, let alone positive 8, can't be divided into 3, you simply leave the fraction as is. So you're left with (h= -8/3)
<em><u>Hope this makes sense.</u></em>