The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
D.
Explanation
I saw this answer in a different question today.
Moreover, 1n + 0.25n = 1.25n
Answer:
(x+12)(x+5)
Step-by-step explanation:
Formula use: a²+bx+c
- Make one side equal to zero:
Original:
-7x-60 =x² +10x
New:
x² + 17x + 60
New:
(1)x x 60 = 60
- Find factors of 60 that when added, equal to 17.
New:
10 × 6, 60 × 1, 20 × 3, <u>5 × 12</u>, 4 × 15
5 times 12 equal 60, but when added equal to 17.
- Replace the 17 with 5 and 12
New:
x² + 5x + 12x + 60
- Break them off into two equations
New:
x² + 5x l 12x + 60
- Divide each equation into it's simpilest form. Make sure the numbers in the ( ) are the same.
New:
x(x + 5) l +12(x+5)
Answer:
84+n=342
Step-by-step explanation:
you would subtract 84 from 342 to find the width since it is perimeter.
Answer:
18
Step-by-step explanation: