Question

Four different ' four 4's problems ( where they all equal a different #) and four different four 4's that equal the same #

Answer 1

Answer:

1=(4/4)*(4/4)

2=(4/4)+(4/4)

3 = (4+4+4)/4

4 = 4 + (4-4)*4

20=4 × (4/4 + 4)

20=4 × (4/4 - (-4))

$20 = \sqrt{4} +\sqrt{4} + (4x4)$

$20 = \sqrt{4} +\sqrt{4} + (-4 x -4)$

Step-by-step explanation:

The x is a multiplication sign not a variable, I hope this right.  Good luck, I am so tired.