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3 years ago

Given the functions, f(x)=4x2 and g(x)=12x2, f(x) is steeper than g(x).

Mathematics

2 answers:

deff fn [24]3 years ago

5 0

The answer shall be true

Svetlanka [38]3 years ago

5 0

Answer:

Step-by-step explanation:

hello :

f(x)=4x² and g(x)=12x²

g(x) = 3(4x²)

g(x)= 3f(x)

f(x) is steeper than g(x) : false

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Semmy [17]

Answer:

Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)

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(7 - 6 = 1)

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(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.

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(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)

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3 years ago

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

OleMash [197]

ANSWER

$x=1.39$ to the nearest hundredth.

EXPLANATION

We have the equation,

$0=2x^2+3x-8$

Which can be rewritten as

$2x^2+3x-8=0$

The question demands the use of the quadratic formula.

Comparing this to the general quadratic equation;

$ax^2+bx+c=0$

$a=2,b=3,c=-8$

The quadratic formula is given by;

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

We now substitute all the values in to the formula;

$x=\frac{-3\pm\sqrt{(3)^2-4(2)(-8)}}{2(2)}$

We simplify to obtain;

$x=\frac{-3\pm\sqrt{9+64}}{4}$

$x=\frac{-3\pm\sqrt{73}}{4}$

We now split the plus or minus sign to obtain;

$x=\frac{-3-\sqrt{73}}{4}$

This implies that;

$x=-2.89$

$x=\frac{-3+\sqrt{73}}{4}$

This will evaluate to;

$x=1.39$

Hence, the positive solution rounded to the nearest hundredth is

$x \approx 1.39$

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