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3 years ago

Given the functions, f(x)=4x2 and g(x)=12x2, f(x) is steeper than g(x).

Mathematics

2 answers:

deff fn [24]3 years ago

5 0

The answer shall be true

Svetlanka [38]3 years ago

5 0

Answer:

Step-by-step explanation:

hello :

f(x)=4x² and g(x)=12x²

g(x) = 3(4x²)

g(x)= 3f(x)

f(x) is steeper than g(x) : false

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2 years ago

What is the solution of √x-5 = x-11

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Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
$\sqrt{x} - 5 = x - 11$

New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

${13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}$

$\frac{13+ \sqrt{25}}{2}$

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$\frac{18}{2}$

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$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

4

So, this means that in the equation $\sqrt{x} -5=x-11$ , x = 9 and x = 4.

Hope this helps!

- Lindsey Frazier ♥

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