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Fantom [35]
3 years ago
10

If we collect a large sample of blood platelet counts and if our sample includes a single​ outlier, how will that outlier appear

in a​ histogram?
Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0
That outlier will appear as a single blip of data, but it will be far away from the central part of the histogram. It will not be that visible if there is a lot of data, since 1 outlying data point will just show a very low height compared to the central data near the mean/median/mode, where there will be higher frequencies and higher bars of data.

If these are the choices:
<span>A.The outlier will appear as a tall bar near one side of the distribution.
B.The outlier will appear as a bar far from all of the other bars with a height that corresponds to a frequency of 1.
C.Since a histogram shows​ frequencies, not individual data​ values, the outlier will not appear.​ Instead, the outlier increases the frequency for its class by 1.
D.The outlier will appear as the tallest bar near the center of the distribution.
</span>
Then the most accurate answer will be B, since it's just a single value with a bar corresponding to a frequency of 1.
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Answer:

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Required

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Differentiate the above function:

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Using Newton's method of approximation, we have:

x_{n+1} = x_n - \frac{h(x_n)}{h'(x_n)}

Plot the graph of h(x) = x -3\sin(x) to get x_1 --- see attachment for graph

From the attached graph, the first value of x is at 2.2; so:

x_1 = 2.2

So, we have:

x_{n+1} = x_n - \frac{h(x_n)}{h'(x_n)}

x_{1+1} = x_1 - \frac{h(x_1)}{h'(x_1)}

x_{2} = 2.2 - \frac{2.2 -3\sin(2.2)}{1 -3\cos(2.2)} = 2.28153641

The process will be repeated until the digit in the 6th decimal place remains unchanged

x_{3} = 2.28153641 - \frac{2.28153641 -3\sin(2.28153641)}{1 -3\cos(2.28153641)} = 2.2788654

x_{4} = 2.2788654 - \frac{2.2788654 -3\sin(2.2788654)}{1 -3\cos(2.2788654)} = 2.2788627

x_{5} = 2.2788627 - \frac{2.2788627-3\sin(2.2788627)}{1 -3\cos(2.2788627)} = 2.2788627

Hence:

x \approx 2.278863

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