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ZanzabumX [31]
3 years ago
9

Atomic Theory

Chemistry
1 answer:
Fynjy0 [20]3 years ago
5 0

Answer:

DASDWSDWSDWS

Explanation:

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How many grams of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel?
Nimfa-mama [501]

Answer: 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

Explanation:

According to the dilution law,

C_1w_1+C_2w_2=C_3w_3

where,

C_1 = concentration of ist progesterone gel = 8%w/w

w_1 = weight of ist progesterone gel  = x g

C_2 = concentration of another progesterone gel  = 4% w/w

w_2 = weight of another progesterone gel = 1.45 g

C_3 = concentration of resulting progesterone gel  = 5.5%w/w

w_3 = weight of resulting progesterone gel  = (x+1.45) g

8\times x+4\times 1.45=5.5\times (x+1.45)

x=0.87

Thus 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

4 0
4 years ago
Thermal energy chemical change lab report
natulia [17]

Answer:

This is required answer.

Explanation:

Given that,

Thermal energy chemical change lab report

We know that,

Thermal energy :

When we rise a temperature of any substance then the molecules of substance moves fastly then the heat produced. It is called thermal energy.

Chemical change in the thermal energy  :

When we heat a substance then the thermal energy increases and the molecules of substance moves fastly. That means the chemical bonds are break in reactants due to energy.

In products, The new chemical bonds are create due to energy.

For example ; The coal is burned then produced heats water and change it into steam.

Hence, This is required answer.

5 0
3 years ago
1
Shtirlitz [24]

Answer:

I believe the answer to be period 3 group 1

8 0
3 years ago
Grape soda is a solution of the solutes carbon dioxide (CO2), sugar (C12H22°11), and grape flavoring (CHNO2) dissolved in
ser-zykov [4K]

Answer:

The ameliorated retort, pertaining to the presented and contemporaneous interrogate is acknowledged as B.  

Explanation:

To convey such rhetoric, the following is obligated for comprehension:

- To commence, according to Wikipedia, a "Pure Substance" is defined as: "A chemical substance is a form of matter having constant chemical composition and characteristic properties. Some references add that chemical substance cannot be separated into its constituent elements by physical separation methods, i.e., without breaking chemical bonds."

- In addition, invariantly according to Wikipedia, a "Chemical Mixture" is defined as: "In chemistry, a mixture is a material made up of two or more different substances which are not chemically combined. A mixture is the physical combination of two or more substances in which the identities are retained and are mixed in the form of solutions, suspensions and colloids."

Hence, veracious retorts are subject to commence.

Given peculiar substances,

H20, an optical isomer is in recognition as a pure substance.

Likewise, CO2, an enantiomer is in the congruence of a pure substance.

Hence, methyl anthranilate acquiring a chemical formula of C8H9NO2, acknowledged as grape flavoring, is a mixture.

Invariantly, the diasteromer epimer, procuring a chemical formula configuration of C12H22O11, sucrose, is acknowledged as a mixture.

Hence, ideologically, the retort in the congruence of veracious philosophy is B. "The pure substances are carbon dioxide and water; mixtures are sugar and grape flavoring."

I hope this helps!

8 0
3 years ago
Chem timed exam, help plz
Alchen [17]

Answer:

3.864 g of C₃H₆

Explanation:

The balanced equation for the reaction is given below:

2C₃H₆ + 9O₂ —> 6CO₂ + 6H₂O

From the balanced equation above,

2 moles of C₃H₆ reacted to produce 6 moles of CO₂

Next, we shall determine the number of mole of C₃H₆ that reacted to produce 0.276 mole of CO₂. This can be obtained as follow:

From the balanced equation above,

2 moles of C₃H₆ reacted to produce 6 moles of CO₂.

Therefore, Xmol of C₃H₆ will react to produce 0.276 moles of CO₂ i.e

Xmol of C₃H₆ = (2 × 0.276)/6

Xmol of C₃H₆ = 0.092 mole

Finally, we shall determine the mass of 0.092 mole of C₃H₆. This can be obtained as follow:

Mole of C₃H₆ = 0.092 mole

Molar mass of C₃H₆ = (12×3) + (6×1)

= 36 + 6

= 42 g/mol

Mass of C₃H₆ =?

Mass = mole × molar mass

Mass of C₃H₆ = 0.092 × 42

Mass of C₃H₆ = 3.864 g

Therefore, 3.864 g of C₃H₆ is needed for the reaction.

5 0
3 years ago
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