Answer:
0.02052M
Explanation:
First, we need to write a balanced equation for the reaction. This is illustrated below:
2KCl + Pb(NO3)2 → 2KNO3 + PbCl2
The following were obtained from the question:
Molarity of Pb(NO3)2 = 0.0229M
Volume of Pb(NO3)2 = 22.40 = 22.4/1000 = 0.0224L
Number of mole of Pb(NO3)2 =?
Recall:
Mole = Molarity x Volume
Mole of Pb(NO3)2 = 0.0229x0.0224
Mole of Pb(NO3)2 = 5.13x10^-4mole
From the equation,
1mole of Pb(NO3)2 required 2moles KCl.
Therefore, 5.13x10^-4mole of Pb(NO3)2 will require = 5.13x10^-4x2 = 1.026x10^-3mole of KCl.
Now we can use this amount (i.e 1.026x10^-3mole) to find the molarity of KCl. This is illustrated below:
Mole of KCl = 1.026x10^-3mole
Volume of KCl = 500mL = 50/1000 = 0.05L
Molarity =?
Molarity = mole /Volume
Molarity of KCl = 1.026x10^-3/0.05
Molarity of KCl = 0.02052M
