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Ivanshal [37]
4 years ago
5

A piece of iron (CsFe = 0.45 J/g·⁰C) with a mass of 4.45 g at temperature of 101.0 oC is dropped into an insulated calorimeter c

ontaining 50.0 g of water at 22.00 oC. What will be the final temperature of the water?
Chemistry
1 answer:
OleMash [197]4 years ago
3 0

Answer:

22.75 ⁰C.

Explanation:

  • The amount of heat added to a substance (Q) can be calculated from the relation:

Q = m.c.ΔT.

where, Q is the amount of heat added,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the temperature difference (final T - initial T).

∵ The amount of heat released by Fe = the amount of heat absorbed by water

<em>∴ - (m.c.ΔT) released by Fe = (m.c.ΔT) absorbed by water.</em>

- (4.45 g)(0.45 J/g·⁰C)(final T - 101.0 ⁰C) = (50.0 g)(4.186 J/g·⁰C)(final T - 22.0 ⁰C)

- 2.0025 final T + 202.2525 = 209.3 final T - 4604.

209.3 final T + 2.0025 final T = 202.2525 + 4604

211.3025 final T = 4806.2525.

<em>final T = 4806.2525/211.3025 = 22.75 ⁰C.</em>

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