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BlackZzzverrR [31]
2 years ago
9

1. Which of the following correctly represents a balance chemical equation? (a) NaCl + 2H2O → 2NaOH + 2Cl2 + H2 (b) 2NaCl+H2O →

2NaOH + 2Cl2 +H, (C) 2NaCl+2H,0 → 2NaOH +Cl2 +H, + (d) 2NaCl + 2H2O → NaOH + CO2 + H2​
Chemistry
1 answer:
butalik [34]2 years ago
8 0

Answer:

thx sa points

Explanation:

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11
Ad libitum [116K]

Explanation:

No because the person on the bike is going faster then the person on foot.

8 0
3 years ago
A breakfast of cereal, orange juice, and milk might contain 230 nutritional Calories. How much is this in Joules?
Sophie [7]

Answer:

B

Explanation:

962,320 J

230 nutritional Calories in Joules is 962,320 J

4 0
1 year ago
The isomers butane and methyl propane have
madreJ [45]

Explanation:

“The isomers butane and methyl propane have the same molecular formula and different properties”, this is because structural isomers usually have different properties to their parent.

3 0
3 years ago
The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc
jek_recluse [69]

Answer: K_{sp}=1.25\times 10^{-14}

pK_{sp}=13.90

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}  

The equation for the ionization of magnesium phosphate is given as:

Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}

 When the solubility of Mg_3(PO_4)_2 is S moles/liter, then the solubility of Mg^{2+} will be 3S moles\liter and solubility of PO_4^{3-} will be 2S moles/liter.

Thus S = 0.173 g/L or \frac{0.173g/L}{262.8g/mol}=0.00065mol/L

K_{sp}=(3S)^3\times (2S)^2

K_{sp}=108S^5

K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}

pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90

5 0
3 years ago
35.5 moles of lithium fluoride is dissolved in 65 L of solution
kkurt [141]

Answer:

Explanation:

L

=

1.10

L

of solution

Explanation:

The Molarity

M

is calculated by the equation comparing moles of solute to liters of solution

M

=

m

o

l

L

For this question we are given the Molarity 0.88M

We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride

We can convert the mass of LiF to moles by dividing by the molar mass of LiF

Li = 6.94

F = 19.0

LiF = 25.94 g/mole

25.2

g

r

a

m

s

x

1

m

o

l

25.94

g

r

a

m

s

=

0.97

moles

Now we can take the the molarity and the moles and calculate the Liters of solution

M

=

m

o

l

L

M

L

=

m

o

l

L

=

m

o

l

M

L

=

0.97

m

o

l

0.88

M

L

=

1.10

L

of solution i just did look at my papaer

3 0
3 years ago
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