Answer:
7.32g of HNO3 are required.
Explanation:
1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.
From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.
2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:
• starting with the 4.30 grams of Ca(OH)2.
,• using the molar mass of Ca(OH)2 (74g/mol).
,• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .
,• using the molar mass of HNO3 (63.02g/mol).
So, 7.32g of HNO3 are required.