<u>Lock your device screen when not in use and require a password to reactivate</u> is not a best practice to protect data on your mobile computing device.
<h3>What is a
mobile computing device?</h3>
Any device that was built using mobile parts, such as mobile hardware and software, is referred to as a mobile computing device. Portable devices that can function like a typical computing device in terms of operation, execution, and provision of services and applications are known as mobile computing devices.
Portable and handheld computing devices are other names for mobile computing devices.
Modern handheld devices that have the hardware and software needed to run common desktop and Web applications are generally referred to as mobile computing devices. Similar hardware and software elements found in personal computers, such as processors, random memory and storage, Wi-Fi, and an operating system, are also found in mobile computing devices. They are made specifically for mobile architecture and portability, which sets them apart from PCS.
Learn more about mobile computing devices
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Answer:
The right response is "Robots
".
Explanation:
- A robot seems to be an independent machine that can detect its surroundings, conduct simulations, as well as take action throughout the modern or actual environment.
- It is indeed a piece of computer-controlled equipment, which would also be utilized autonomously for carrying out duties or other hazardous tasks.
Answer:
oid changeCase (char char_array[], int array_size ) {
__asm{
mov eax, char_array;
mov edi, 0;
readArray:
cmp edi, array_size;
jge exit;
mov ebx, edi;
shl ebx, 2;
mov cl, [eax + ebx];
check:
//working on it
cmp cl, 0x41;
jl next_indx;
cmp cl, 0x7A;
jg next_indx;
cmp cl, 'a';
jl convert_down;
jge convert_up;
convert_down:
or cl, 0x20; //make it lowercase
jmp write;
convert_up:
and cl, 0x20;
jmp write;
write:
mov byte ptr [eax + ebx], cl
next_indx:
inc edi;
exit:
cmp edi, array_size;
jl readArray;
mov char_array, eax;
}
}
Explanation:
- Move char_array to eax as it is base image
.
- Use ebx as offset
.
- Use ecx as the storage register
.
- check if cl is <= than ASCII value 65 (A)
.
A copy and paste would be fastest and easiest. As you can pinpoint the exact location to where you want the picture to be.
