Answer: x = 8
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I'm going to use the notation log(2,x) to indicate "log base 2 of x". The first number is the base while the second is the expression inside the log (aka the argument of the log)
log(2,x) + log(2,(x-6)) = 4
log(2,x*(x-6)) = 4
x*(x-6) = 2^4
x*(x-6) = 16
x^2-6x = 16
x^2-6x-16 = 0
(x-8)(x+2) = 0
x-8 = 0 or x+2 = 0
x = 8 or x = -2
Recall that the domain of log(x) is x > 0. So x = -2 is not allowed. The same applies to log(2,x) as well.
Only x = 8 is a proper solution.
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You can use the change of base rule to check your work
log base 2 of x = log(2,x) = log(x)/log(2)
log(2,(x-6)) = log(x-6)/log(2)
So,
(log(x)/log(2)) + (log(x-6)/log(2)) = 4
(log(8)/log(2)) + (log(8-6)/log(2)) = 4
(log(8)/log(2)) + (log(2)/log(2)) = 4
(log(2^3)/log(2)) + (log(2)/log(2)) = 4
(3*log(2)/log(2)) + (log(2)/log(2)) = 4
3+1 = 4
4 = 4
The answer is confirmed
I think you find 18.63% of $835 and then you get your answer. I am pretty sure it is $155.56, hope this helps.
Answer:
The computation of the given question is shown below:-
Total Contributions = Monthly contribution + Amount invested in Ferdinand’s 401(k)
= $250 + $125
= $375
1. Future Value = PMT [((1 + r)n - 1) ÷ r
Future value = 375 × ((1 + 0.03 ÷ 12) × 12 × 40 - 1) ÷ (0.03 ÷ 12)
= $347,272
2. Ferdinand deposit = Given Amount × Total number of months in a year × Number of years
= $250 × 12 Months × 40 Years
= $120,000
3. The Amount put in by the employer = 50% of $250 ×Total number of months in a year × Number of years
= $125 × 12 Months × 40 Years
= $60,000
4. Interest = Future value - Ferdinand deposit - The Amount put in by the employer
= $347,272 - $120,000 - $60,000
= $167,272
Step-by-step explanation:
Answer:
y = -3x -4
Step-by-step explanation:
A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.
The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.
The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...
3(x+3) +(y-5) = 0
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This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:
3x +9 +y -5 = 0 . . . . . eliminate parentheses
y = -3x -4 . . . . . subtract terms that are not "y"
Answer:
Step-by-step explanation:
It's easier to convert the angle into degrees.
5π/8 ≅ 112.5°, which is in quadrant II
