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3 years ago

15

Nicki shows a magic trick to three of her freinds. Each of those freinds shows it to three more freinds. If the pattern is repea

ted two more times, how many people now know the trick?

1 answer:

Inga [223]3 years ago

8 0

Answer:

109

Step-by-step explanation:

Hopw it helps :).

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A farmer has a rectangular field that measures 100 feet by 150 feet. He plans to increase the area of the field by 20%. He will

aliya0001 [1]

Answer:

(100 + x) x (150 + x) = 18,000 ft^2

Step-by-step explanation:

area of a rectangle = length x width

Area of the original field = 15,000

Area after 20% increase = 1.2 x 15,000 = 18,000

Increase i length = 100 + x

increase i width = 150 + x

Area = (100 + x) x (150 + x) = 18,000 ft^2

7 0

3 years ago

Read 2 more answers

Are 2,3,4,5,6,9,10 divisble by 3

babunello [35]

No, only 3, 6, and 9 are divisible by 3 because 3 x 1= 3, 3 x 2= 6, 3 x 3= 9. Hope this helps

8 0

3 years ago

Read 2 more answers

Which of the following points satisfies the inequality y>1/3x-2 which side should be shaded

garik1379 [7]

Answer: Hope this helps <3

Step-by-step explanation:

4 0

4 years ago

X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4

AfilCa [17]

Given a solution $y_1(x)=x^4$ , we can attempt to find another via reduction of order of the form $y_2(x)=x^4v(x)$ . This has derivatives

${y_2}'=4x^3v+x^4v'$
${y_2}''=12x^2v+8x^3v'+x^4v''$

Substituting into the ODE yields

$x^2(x^4v''+8x^3v'+12x^2v)-7x(x^4v'+4x^3v)+16x^4v=0$
$x^6v''+(8x^5-7x^5)v'+(12x^4-28x^4+16x^4)v=0$
$x^6v''+x^5v'=0$

Now letting $u(x)=v'(x)$ , so that $u'(x)=v''(x)$ , you end up with the ODE linear in $u$

$x^6u'+x^5u=0$

Assuming $x\neq0$ (which is reasonable, since $x=0$ is a singular point), you can divide through by $x^5$ and end up with

$xu'+u=(xu)'=0$

and integrating both sides with respect to $x$ gives

$xu=C_1\implies u=\dfrac{C_1}x$

Back-substitute to solve for $v$ :

$v'=\dfrac{C_1}x\implies v=C_1\ln|x|+C_2$

and again to solve for $y$ :

$y=x^4v\implies \dfrac y{x^4}=C_1\ln|x|+C_2$
$\implies y=C_1\underbrace{x^4\ln|x|}_{y_2}+C_2\underbrace{x^4}_{y_1}$

Alternatively, you can solve this ODE from scratch by employing the Euler substitution (which works because this equation is of the Cauchy-Euler type), $t=\ln x$ . You'll arrive at the same solution, but it doesn't hurt to know there's more than one way to solve this.

6 0

3 years ago

Trapezoid ABCD has vertices A (2, 4), B (5, 4), C (7, 1), and D (0, 1). What are the lengths of the sides AD and BC?

Ludmilka [50]

Answer:

√13 ≈ 3.61

Step-by-step explanation:

The distance formula is applicable.

d = √((x2-x1)² +(y2-y1)²)

AD = √((0-2)² +(1-4)²) = √(4+9) = √13

AD ≈ 3.605513 ≈ 3.61

___

The trapezoid is isosceles, so AD and BC are the same length, 3.61.

8 0

3 years ago