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3 years ago

What is the area of a sector when r=9/2 and 0=5pi/6 radians?

Mathematics

1 answer:

lana66690 [7]3 years ago

4 0

Answer:

<h2>Hyy There !! </h2>

Step-by-step explanation:

<h3><u>Question Says :- </u></h3>

• The Area of a sector when r = 9/2 and

θ = 5pi/6 radians ? .

? pi / ?

<h3><u>Circular Area of a Sector</u></h3>

Problems involving area of a sector can be solved easily. One should just obtain two essential information from the circle of interest, the central angle measure θ and radius r For angle measures in radians, the area A is calculated as :-

<h3>Hope this helps you !! </h3>

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Examine the following sequence 1, 4, 9, 16, 25.... Why is 36 the next number in the sequence? Because the pattern

ki77a [65]

Answer:

Step-by-step explanation:

1,4,9,16,25,36,...

we see every number is square of numbers .

every number can be represented by n²

1²=1

2²=4

3²=9

4²=16

5²=25

6²=36

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3 years ago

The table below shows the average yearly balance in a savings

svet-max [94.6K]

Its d.exponential growth function b/c how it is written and how big it gets really fast. :) hope this helps

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3 years ago

The number of bags of mulch you need to cover a planting area varies jointly with the area to be mulched (a) in sq ft and the de

Lena [83]

Answer:

22 2/9

Step-by-step explanation:

When z "varies jointly" with x and y, it can be described by the formula

z = kxy

Here, we have bags of mulch (n) varying jointly with area (a) and depth (d), both in feet. The given information can let us find the value of k.

n = kad

10 = k·(120)(1/4)

10/30 = k = 1/3 . . . . . divide by the coefficient of k

Now, we can fill in the other values of interest.

n = (1/3)·(200)·(1/3) = 200/9

n = 22 2/9

You need 22 2/9 bags of mulch to cover 200 ft² to a depth of 4 inches.

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<em>Comment on the problem</em>

This problem requires the formula be written with both area and depth expressed in feet, yet it gives depth in inches. The formula can also be written using depth in inches. In that case, k = 1/36.

8 0

3 years ago

Use the given information to find the unknown value:y varies inversely with a. When x = 4, then y= 4. Find y when I = 2.Iyy =hel

Mashutka [201]

Inverse variation:

$y=\frac{k}{x}$

k is a constant

Use the given information (when x=4 y=4) to find the value of the constant:

$\begin{gathered} 4=\frac{k}{4} \\ \\ \text{Multiply both sides of the equation by 4:} \\ 4\times4=4\times\frac{k}{4} \\ \\ 16=k \\ \\ \\ k=16 \end{gathered}$

Then, the given relationship has the next equation:

$y=\frac{16}{x}$

Use the equation above to find y when x=2:

$\begin{gathered} y=\frac{16}{2} \\ \\ y=8 \end{gathered}$ Then, when x=2, y=8

3 0

1 year ago

I need help with this

Kruka [31]

Answer:

X=9/4

Step-by-step explanation:

-3x+10=5x-8

Subtract 10 from each sides

-3x=5x-18

Subtract 5x from both sides

-8x=-18

Divide both sides by -8

x=9/4

I hope this helped

3 0

3 years ago