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Galina-37 [17]
3 years ago
10

Im going to keep coming with math questions so answer as many as you can correctly, i have to get an A o B on this quiz!

Mathematics
1 answer:
Julli [10]3 years ago
5 0
The answer would be x = 88

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Water is placed in a cellular bucket on a bench The book has a diameter of 12 in and a height of 12 in The bucket is capable of
Ilya [14]

Answer:

bucket of water = 50.397 lbs

Step-by-step explanation:

Pi(r^2)(h) = volume

3.14(6^2)(12) = 1356.48 in^3 = volume of bucket

one ft^3 = 12 x 12 x 12 = 1728 in^3

1356.48/1728 = 0.785 ft^3 (volume of bucket)

0.785(64.2) = 50.397 lbs

6 0
3 years ago
Which equation represents a proportional relationship?
bonufazy [111]
It's the first one. y = 3x
proportional means they are just some multiple of the other.
4 0
3 years ago
Read 2 more answers
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
In which expression should the exponents be multiplied? 1. one fifth to the 2nd times one fifth to the 6th 2. 9 to the 3rd over
Paul [167]

Answer:

4. (2^6)^-5.

an number to an exponent to another exponent is multiplied

6 0
3 years ago
The sum of the digits of a two-digit
Ann [662]

Answer:

45

Step-by-step explanation:

Let the unit place be ‘x'

Tenth place be y

The number is 10y+x

x+y = 9 (according to the condition) (1)

Digits are interchanged Unit place' y ‘& tenth place ‘ x'

New no is 10x +y

This is 9 more than the original number

10x+ y = 10y+x +9

10x-x+y-10y = 9

9x-9y= 9

x-y = 1 (dividing by 9) (2)

Adding the two equations

2x = 10

x= 5

Substituting the value of x in first equation

y = 4

The number is 45, the original number is 54 this is 9 more of the new number.

6 0
3 years ago
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